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Amine (List–I) | List - II pKb (aqueous medium) | ||
A. | Aniline | (i) | 9.0 |
B. | Ethanamine | (ii) | 3.29 |
C. | N-Ethylethanamine | (iii) | 3.25 |
D. | N,N-diethylethanamine | (iv) | 3.0 |
A | B | C | D | |
1. | (i) | (ii) | (iv) | (iii) |
2. | (i) | (iv) | (iii) | (ii) |
3. | (i) | (ii) | (iii) | (iv) |
4. | (ii) | (iii) | (iv) | (i) |
1. | A is |
2. | B is |
3. | C is |
4. | D is |
1. | 2 > 1 > 3 > 4 | 2. | 3 > 2 > 1> 4 |
3. | 4 > 2 > 1> 3 | 4. | 2 > 4 > 3 > 1 |
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1. | \(SOCl_2 ,KCN , H_2 /Pd \) |
2. | \(SOCl_2 ,AgCN , H_2 /Pd \) |
3. | \(PCl_5 ,AgCN , H_2 /Pd \) |
4. | Red P/HI |
Statement I: | In the Hofmann rearrangement reaction, the alkyl group shifts from a carbonyl carbon atom to the nitrogen atom. |
Statement II: | The tertiary amine formed in Hofman rearrangement reaction contains one carbon less than that present in the original amide. |
1. | Both Statement I & Statement II are true. |
2. | Both Statement I & Statement II are false. |
3. | Statement I is true while Statement II is false. |
4. | Statement I is false while Statement II is true. |
Identify the product formed from the reaction of chloroform with alcoholic KOH and p-toluidine.
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