Among the following, which are amphoteric oxides?
1. V2O5, Cr2O3
2. Mn2O7, CrO3
3. CrO, V2O5
4. V2O5, V2O4
Highest oxidation state of manganese in fluoride is +4 (Mn) but the highest oxidation state in oxides is +7 (Mn2O7). The reason is :
1. | Fluorine is more electronegative than oxygen. |
2. | Fluorine does not possess d orbitals. |
3. | Fluorine stabilizes lower oxidation state of Mn. |
4. | In covalent compounds, fluorine can only form a single bond while oxygen forms a double bond. |
Based on the metallic radii provided, which transition element exhibits the highest density?
Element | Fe | Co | Ti | Cu |
Metallic radii/pm | 126 | 125 | 147 | 128 |
1. Fe
2. Ti
3. Co
4. Cu
The electronic configuration of gadolinium (atomic number of 64) is:
1.
2.
3.
4.
Match Column I (Catalyst) with Column II (Process), and mark the appropriate option:
Column I - (Catalyst) | Column II - (Process) | ||
A. | Ni in the presence of hydrogen | 1. | Contact process |
B. | Cu2Cl2 | 2. | Vegetable oil to ghee |
C. | V2O5 | 3. | Sandmeyer reaction |
D. | Finely divided iron | 4. | Haber's process |
5. | Decomposition of KClO3 |
Codes:
A | B | C | D | |
1. | 3 | 4 | 2 | 5 |
2. | 2 | 3 | 1 | 4 |
3. | 5 | 4 | 3 | 2 |
4. | 4 | 5 | 3 | 2 |
Urea reacts with water to form A, which decomposes to form B. When B is passed through (aq), a deep blue-colored solution C is formed
The formula of C is:
2.
3.
4.
Match the following characteristics to the appropriate metal:
Column I - Aspects | Column II - Metal | ||
(a) | The metal which reveals the maximum number of oxidation states | (i) | Scandium |
(b) | The metal although placed in 3d block is considered not as a transition element | (ii) | Copper |
(c) | The metal which does not exhibit variable oxidation states | (iii) | Manganese |
(d) | The metal which in +1 oxidation state in aqueous solution undergoes disproportionation | (iv) | Zinc |
Select the correct option :
(a) | (b) | (c) | (d) | |
1. | (i) | (iv) | (ii) | (iii) |
2. | (iii) | (iv) | (i) | (ii) |
3. | (iii) | (i) | (iv) | (ii) |
4. | (ii) | (iv) | (i) | (iii) |
Actinoids show a greater number of oxidation states than lanthanoids because:
1. | 4f- orbitals are more diffused than 5f-orbitals |
2. | Lesser energy difference between 5f, and 6d orbitals than between 4f, and 5d orbitals |
3. | More energy difference between 5f, and 6d orbitals than between 4f, and 5d orbitals |
4. | More reactive nature of the actinoids than the lanthanoids. |
Which of the following is a result of the lanthanide contraction?
1. Zr and Y have nearly the same atomic radius.
2. Zr and Zn have the same oxidation state.
3. Zr and Hf have nearly the same atomic radius.
4. Zr and Nb have similar oxidation states.
The oxidation state of chromium in the final product formed by the reaction between KI and acidified potassium dichromate solution will be:
1. +2
2. +3
3. +4
4. +6