Pink colour of acidified \(KMnO_4\) is decolourised but there is no evolution of any gas. This may happen with the compound containing the following acid radical (s):
1.
\(SO^{2-}_3\)
2.
\(NO^{-}_2\)
3.
\(S^{2-}\)
4.
All of the above
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Subtopic: Detection of Anions |
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Salt (A), when heated, releases a colorless neutral gas that supports combustion. Based on the diagram provided, it can be concluded that compound (A) contains the following acid radical:
1.
\(\mathrm{NO}_2^{-} \)
2.
\(\mathrm{NO}_3^{-} \)
3.
\(\mathrm{Br}^ - \)
4.
\(\mathrm{SO}_3{ }^{2-}\)
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The solution of a chemical compound (X) reacts with \(AgNO_3\) solution to form a white precipitate of (Y) which in turn dissolves in \(NH_4OH \) to give a complex (Z). When (Z) is treated with dilute \(HNO_3,\) (Y) reappears. The chemical compound X can be :
1. \(NaCl \)
2. \(CH_3Cl \)
3. \(NaBr \)
4. \(NaI \)
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Subtopic: Detection of the functional groups |
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A gas (X) is passed through water to form a saturated solution. The aqueous solution on treatment with silver nitrate gives a white precipitate. The saturated aqueous solution also dissolves magnesium ribbon with the evolution of a colourless gas (Y). X and Y, respectively, are:
1. \(X= CO_2,~Y=Cl_2 \)
2. \(X= Cl_2,~Y=CO_2 \)
3. \(X= Cl_2,~Y=H \)
4. \(X= H,~Y=Cl_2 \)
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On adding \(KI\) solution in excess to a solution of \(CuSO_4\) we get a precipitate 'P and another liquor M. Select the correct pairs:
1. P is \(Cu_2I_2 \) and M is \(I_2\) solution
2. P is \(CuI_2 \) and M is \(I_2\) solution
3. P is \(Cu_2I_2 \) and M is \(KI_3\) solution
4. P is \(CuI_2 \) and M is \(KI_3\) solution
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