A body is falling freely in a resistive medium. The motion of the body is described by \(\dfrac{dv}{dt}=(4-2v), \) where \(v\) is the velocity of the body at any instant (in \(\text{ms}^{–1}\)). The terminal velocity in this case refers to the velocity the body approaches as time \(t \to \infty.\) The initial acceleration and terminal velocity of the body, respectively, are:

1. \(4~\text{m/s}^2,\) \(2~\text{m/s}\) 2. \(2~\text{m/s}^2,\) \(4~\text{m/s}\)
3. \(6~\text{m/s}^2,\) \(2~\text{m/s}\) 4. \(2~\text{m/s}^2,\) \(6~\text{m/s}\)
Subtopic:  Acceleration |
 63%
Level 2: 60%+
NEET - 2024
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The motion of a particle along a straight line is described by the equation \(x = 8+12t-t^3\) where \(x \) is in meter and \(t\) in seconds. The retardation of the particle, when its velocity becomes zero, is:

1. \(24\) ms-2 2. zero
3. \(6\) ms-2 4. \(12\) ms-2
Subtopic:  Acceleration |
 78%
Level 2: 60%+
AIPMT - 2012
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