- 1(current)
Q. No.\(10\) resistors, each of resistance \(R\) are connected in series to a battery of \(E\) and negligible internal resistance. Then those are connected in parallel to the same battery, the current is increased \(n\) times. The value of \(n\) is:
| 1. | \(1000\) | 2. | \(10\) |
| 3. | \(100\) | 4. | \(1\) |
Subtopic: Â Combination of Resistors |
 70%
Level 2: 60%+
NEET - 2023
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The equivalent resistance of the infinite network given below is:
| 1. | \(2~\Omega\) | 2. | \((1+\sqrt2)~\Omega\) |
| 3. | \((1+\sqrt3)~\Omega\) | 4. | \((1+\sqrt5)~\Omega\) |
Subtopic: Â Combination of Resistors |
 55%
Level 3: 35%-60%
NEET - 2022
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A \(12\) cm wire is given a shape of a right-angled triangle \(\mathrm{ABC}\) having sides \(3\) cm, \(4\) cm and \(5\) cm, as shown in the figure. The resistance between two ends \((\mathrm{AB, BC, CA})\) of the respective sides are measured one by one by a multi-meter. The resistances will be in the ratio:
1. \(9:16:25\)
2. \(27:32:35\)
3. \(21:24:25\)
4. \(3:4:5\)
1. \(9:16:25\)
2. \(27:32:35\)
3. \(21:24:25\)
4. \(3:4:5\)
Subtopic: Â Combination of Resistors |
Level 3: 35%-60%
NEET - 2013
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A ring is made of a wire having a resistance of \(R_0=12~\Omega.\). Find points \(\mathrm{A}\) and \(\mathrm{B}\), as shown in the figure, at which a current-carrying conductor should be connected so that the resistance \(R\) of the subcircuit between these points equals \(\frac{8}{3}~\Omega\)
| 1. | \(\dfrac{l_1}{l_2} = \dfrac{5}{8}\) | 2. | \(\dfrac{l_1}{l_2} = \dfrac{1}{3}\) |
| 3. | \(\dfrac{l_1}{l_2} = \dfrac{3}{8}\) | 4. | \(\dfrac{l_1}{l_2} = \dfrac{1}{2}\) |
Subtopic: Â Combination of Resistors |
 53%
Level 3: 35%-60%
AIPMT - 2012
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- 1(current)
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