What mass of glucose (C₆H₁₂O₆) must be dissolved in 1 liter of solution to make it isotonic with a 15 g/L solution of urea (NH₂CONH₂)?

(Given : Molar mass in g \(\mathrm{mol}^{-1}\) C:12, H:1, O: 16, N:14)

1. 55 g 
2. 15 g 
3. 30 g
4. 45 g
Subtopic:  Concentration Terms & Henry's Law | Osmosis & Osmotic Pressure |
 77%
Level 2: 60%+
NEET - 2024
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The Henry's law constant KH values of three gases (A, B, C) in water are 145, 2 × 10–5, and 35 kbar, respectively. Determine the order of solubility of these gases in water from highest to lowest:
1. B > C > A 2. A > C > B
3. A > B > C 4. B > A > C
Subtopic:  Concentration Terms & Henry's Law |
 61%
Level 2: 60%+
NEET - 2024
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Given below are two statements: one is labeled as Assertion (A) and the other is labeled as Reason (R): 
Assertion (A): Helium is used to dilute oxygen in the diving apparatus. 
Reason (R): Helium has a high solubility in O2.
In light of the above statements, choose the correct answer from the options given below:
1. (A) is False but (R) is True.
2. Both (A) and (R) are True and (R) is the correct explanation of (A)
3. Both (A) and (R) are True and (R) is not the correct explanation of (A).
4. (A) is True but (R) is False.
Subtopic:  Concentration Terms & Henry's Law |
 51%
Level 3: 35%-60%
NEET - 2023
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Which of the following contains 0.5 moles of a solute in one molal solution?
1. 1000 g of solvent 2. 500 mL of solvent
3. 500 g of solvent 4. 100 mL of solvent
Subtopic:  Concentration Terms & Henry's Law |
 74%
Level 2: 60%+
NEET - 2022
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pA and pB are the vapour pressure of pure liquid components, A and B, respectively of an ideal binary solution.
If XA represents the mole fraction of component A, the total pressure of the solution will be:

1. pA + XA (pB-pA) 2. pA + X(pA-pB)
3. pB + X(pB-pA) 4. pB + X(pA-pB)
Subtopic:  Dalton’s Law of Partial Pressure |
 73%
Level 2: 60%+
AIPMT - 2012
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Which of the following is true, when \(5\) moles of liquid \(\text X\) and \(10\) moles of liquid \(\text Y\) make a solution having a vapour pressure of \(70\) torr?
[Given: The vapour pressures of pure \(\text X\) and \(\text Y\) are \(63\) torr and \(78\) torr respectively]
1. The solution is ideal. 
2. The solution has a volume that is greater than the sum of individual volumes. 
3. The solution shows positive deviation. 
4. The solution shows negative deviation. 
Subtopic:  Raoult's Law |
 56%
Level 3: 35%-60%
NEET - 2025
Please attempt this question first.
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Please attempt this question first.

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The mixture that shows positive deviation from Raoult's law is:

1. Benzene + Toluene

2. Acetone + Chloroform

3. Chloroethane + Bromoethane

4. Ethanol + Acetone

Subtopic:  Raoult's Law |
 69%
Level 2: 60%+
NEET - 2020
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The correct statement regarding a solution of two components A and B exhibiting positive deviation from ideal behaviour is :

1. Intermolecular attractive force between A-A and B-B are stronger than those between A-B
2. mixH = 0 at constant T and P
3. mixV = 0 at constant T and P
4. Intermolecular attractive forces between A-A and B-B are equal to those between A-B
Subtopic:  Raoult's Law |
 86%
Level 1: 80%+
NEET - 2019
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For an ideal solution, the correct option is:

1. mix G=0 at constant T and P

2. mix S=0 at constant T and P

3. mix V0 at constant T and P

4. mix H=0 at constant T and P

Subtopic:  Raoult's Law |
 82%
Level 1: 80%+
NEET - 2019
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Vapour pressure of chloroform \(\mathrm{(CHCl_3)}\) and dichloromethane \(\mathrm{(CH_2Cl_2)}\) at 25°C are 200 mmHg and 41.5 mmHg respectively. Vapour pressure of the solution was obtained by mixing 25.5 g of \(\mathrm{(CHCl_3)}\) and 40 g of \(\mathrm{(CH_2Cl_2)}\) at the same temperature will be: (Molecular mass of \(\mathrm{(CHCl_3)}\) = 119.5 u and molecular mass of \(\mathrm{(CH_2Cl_2)}\) = 85 u)

1. 90.40 mm Hg 2. 119.5 mm Hg 
3. 75 mm Hg  4. 173.9 mm Hg 
Subtopic:  Raoult's Law |
 55%
Level 3: 35%-60%
AIPMT - 2012
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