What mass of glucose (C₆H₁₂O₆) must be dissolved in 1 liter of solution to make it isotonic with a 15 g/L solution of urea (NH₂CONH₂)?
(Given : Molar mass in g \(\mathrm{mol}^{-1}\) C:12, H:1, O: 16, N:14)| 1. | B > C > A | 2. | A > C > B |
| 3. | A > B > C | 4. | B > A > C |
| Assertion (A): | Helium is used to dilute oxygen in the diving apparatus. |
| Reason (R): | Helium has a high solubility in O2. |
| 1. | (A) is False but (R) is True. |
| 2. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 3. | Both (A) and (R) are True and (R) is not the correct explanation of (A). |
| 4. | (A) is True but (R) is False. |
| 1. | 1000 g of solvent | 2. | 500 mL of solvent |
| 3. | 500 g of solvent | 4. | 100 mL of solvent |
pA and pB are the vapour pressure of pure liquid components, A and B, respectively of an ideal binary solution.
If XA represents the mole fraction of component A, the total pressure of the solution will be:
| 1. | pA + XA (pB-pA) | 2. | pA + XA (pA-pB) |
| 3. | pB + XA (pB-pA) | 4. | pB + XA (pA-pB) |
| 1. | The solution is ideal. |
| 2. | The solution has a volume that is greater than the sum of individual volumes. |
| 3. | The solution shows positive deviation. |
| 4. | The solution shows negative deviation. |
1. Benzene + Toluene
2. Acetone + Chloroform
3. Chloroethane + Bromoethane
4. Ethanol + Acetone
The correct statement regarding a solution of two components A and B exhibiting positive deviation from ideal behaviour is :
| 1. | Intermolecular attractive force between A-A and B-B are stronger than those between A-B |
| 2. | ∆mixH = 0 at constant T and P |
| 3. | ∆mixV = 0 at constant T and P |
| 4. | Intermolecular attractive forces between A-A and B-B are equal to those between A-B |
For an ideal solution, the correct option is:
1. at constant T and P
2. at constant T and P
3. at constant T and P
4. at constant T and P
Vapour pressure of chloroform \(\mathrm{(CHCl_3)}\) and dichloromethane \(\mathrm{(CH_2Cl_2)}\) at are 200 mmHg and 41.5 mmHg respectively. Vapour pressure of the solution was obtained by mixing 25.5 g of \(\mathrm{(CHCl_3)}\) and 40 g of \(\mathrm{(CH_2Cl_2)}\) at the same temperature will be: (Molecular mass of \(\mathrm{(CHCl_3)}\) = 119.5 u and molecular mass of \(\mathrm{(CH_2Cl_2)}\) = 85 u)
| 1. | 90.40 mm Hg | 2. | 119.5 mm Hg |
| 3. | 75 mm Hg | 4. | 173.9 mm Hg |