In half wave rectification, if the input frequency is 60 Hz, then the output frequency would be:
1. 120 Hz
2. zero
3. 30 Hz
4. 60 Hz
Subtopic:  Rectifier |
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As the temperature increases, the electrical resistance:
1. decreases for conductors but increases
    for semiconductors
2. increases for both conductors and
    semiconductors
3. decreases for both conductors and
    semiconductors
4. increases for conductors but decreases
    for semiconductors
Subtopic:  Energy Band theory |
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In the given circuits (a), (b) and (c), the potential drop across the two p-n junctions are equal in : 
        
1. Both circuits (a) and (c)
2. Circuit (a) only
3. Circuit (b) only
4. Circuit (c) only
Subtopic:  PN junction |
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The truth table for the given logic circuit is:
1.
A B C
0 0 0
0 1 1
1 0 0
1 1 1
2.
A B C
0 0 0
0 1 1
1 0 1
1 1 0
3.
A B C
0 0 1
0 1 0
1 0 0
1 1 1
4.
A B C
0 0 1
0 1 0
1 0 1
1 1 0
Subtopic:  Logic gates |
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Two amplifiers of voltage gain 20 each, are cascaded in series. If 0.01 volt a.c. input signal is applied across the first amplifier, the output a.c. signal of the second amplifier in volt is:
1.  2.0
2.  4.0
3.  0.01
4.  0.20

Subtopic:  Applications of Transistor |
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The output of the logic circuit shown is equivalent to a/an:
      
1. OR gate
2. NOR gate
3. AND gate
4. NAND gate

Subtopic:  Logic gates |
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The circuit represents a full wave bridge rectifier when switch S is open. The output voltage (V0) pattern across RL when S is closed is:
           

1.
2.
3.
4.
Subtopic:  Applications of PN junction |
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The electron concentration in an n-type semiconductor is the same as hole concentration in a p-type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them.

1. Current in n-type > current in p-type.

2. No current will flow in p-type, current will only flow in n-type.

3. Current in n-type = current in p-type.

4. Current in p-type > current in n-type.

Subtopic:  Types of Semiconductors |
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Consider the following statements (A) and (B) and identify the correct answer. 

A. A zener diode is connected in reverse bias when used as a voltage regulator.

B. The potential barrier of p-n junction lies between 0.2 V to 0.3 V.

1. (A) is correct and (B) is incorrect.

2. (A) is incorrect and (B) is correct.

3. (A) and (B) both are correct.

4. (A) and (B) both are incorrect.

Subtopic:  Applications of PN junction |
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For the given circuit, the input digital signals are applied at the terminals A, B and C. What would be the output at terminal y?

1.
2.
3.
4.
Subtopic:  Logic gates |
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