An LED is constructed from a \(\mathrm{p\text{-}n}\) junction diode using \(\mathrm{GaAsP}\). The energy gap is \(1.9~\text{eV}\). The wavelength of the light emitted will be equal to:
1. \(10.4 \times 10^{-26} \text{m}\)
2. \(654~ \text{nm}\)
3. \(654~ \text{m}\)
4. \(654\times 10^{-11}~\text{m}\)
1. | \(1.0 \times 10^6 ~\text{V/m}\) | 2. | \(1.0 \times 10^5 ~\text{V/m}\) |
3. | \(2.0 \times 10^5 ~\text{V/m}\) | 4. | \(2.0 \times 10^6 ~\text{V/m}\) |
1. | \(5\) A | 2. | \(0.2\) A |
3. | \(0.6\) A | 4. | zero |
1. | \(V_B\) increases, \(x\) decreases | 2. | \(V_B\) decreases, \(x\) increases |
3. | \(V_B\) increases, \(x\) increases | 4. | \(V_B\) decreases, \(x\) decreases |
If the reverse bias in a junction diode is changed from \(5\) V to \(15\) V then the value of current changes from \(38~\mu \text{A}\) to \(88~\mu \text{A}\). The resistance of junction diode will be:
1. \(4\times10^{5}\)
2. \(3\times10^{5}\)
3. \(2\times10^{5}\)
4. \(10^{6}\)
A Zener diode is shown in the following circuit diagram. When the source voltage fluctuates such that \(V>V_z\) then:
1. | \(I_1, I_2~\text{and}~I_3\) change. | all the current
2. | \(I_1\) and \(I_2\) change and \(I_3\) remains constant. | only
3. | \(I_1\) and \(I_3\) change and \(I_2\) remains constant. | only
4. | all the currents remain constant. |
1. \(2\) A and zero
2. \(3\) A and \(2\) A
3. \(2\) A and \(3\) A
4. zero and \(2\) A
1. | 2. | ||
3. | 4. |
The combination of gates shown in the diagram is equivalent to:
1. OR
2. AND
3. NAND
4. NOT
A Zener diode is used to obtain a constant voltage. If applied voltage \(\text V\) changes, then:
(\(\text V\) is more than Zener voltage)
1. | \(i_{1}\) and \(i_{2}\) change. |
2. | \(i_{2}\) and \(\text V_{0}\) change and \(i_{3}\) remains constant. |
3. | \(i_{2}\) and \(\text V_{0}\) don't change while \(i_{3}\) changes. |
4. | \(i_{3}\) and \(\text V_{0}\) don't change while \(i_{2}\) changes. |