If the mass of the iron nucleus is \(55.85~\text{u}\) and \(\mathrm{A} = 56\), the nuclear density of the iron is:

1. \(2.27\times10^{17}~\text{kg m}^{-3}\)
2. \(1.36\times 10^{15}~\text{kg m}^{-3}\)
3. \(3.09\times10^{17}~\text{kg m}^{-3}\)
4. \(4.11\times10^{15}~\text{kg m}^{-3}\)
Subtopic:  Nuclear Binding Energy |
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The energy equivalent of \(1\) g of substance is:
1. \(8.3\times10^{13}~\text{J}\)
2. \(9\times10^{13}~\text{J}\)
3. \(7.7\times10^{13}~\text{J}\)
4. \(11\times10^{13}~\text{J}\)

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We are given the following atomic masses:

U92238 = 238.05079 u, He24= 4.00260 u

Th90234 = 234.04363 u, H11= 1.00783 u

Pa91237= 237.05121 u

Here the symbol Pa is for the element protactinium (Z = 91).

The energy released during the alpha decay of U92238 is:

1. 6.14 MeV 

2. 7.68 MeV 

3. 4.25 MeV

4. 5.01 MeV 

Subtopic:  Nuclear Binding Energy |
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We are given the following atomic masses:

U92238 = 238.05079 u, He24= 4.00260 u

Th90234 = 234.04363 u, H11= 1.00783 u

Pa91237= 237.05121 u

Here the symbol Pa is for the element protactinium (Z = 91).

Then:

1. U92238 can not spontaneously emit a proton.

2. U92238 can spontaneously emit a proton.

3. The Q-value of the process is negative.

4. Both (1) and (3)

Subtopic:  Nuclear Binding Energy |
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