- 1(current)
Q. No.In the given nuclear reaction, the element \(\mathrm{X}\) is:
\({ }_{11}^{22} \mathrm{Na} \rightarrow \mathrm{X}+\mathrm{e}^{+}+\nu\)
1. \({ }_{12}^{22} \mathrm{Mg}\)
2. \({ }_{11}^{23} \mathrm{Na}\)
3. \({ }_{10}^{23} \mathrm{Ne}\)
4. \(_{10}^{22}\textrm{Ne}\)
\({ }_{11}^{22} \mathrm{Na} \rightarrow \mathrm{X}+\mathrm{e}^{+}+\nu\)
1. \({ }_{12}^{22} \mathrm{Mg}\)
2. \({ }_{11}^{23} \mathrm{Na}\)
3. \({ }_{10}^{23} \mathrm{Ne}\)
4. \(_{10}^{22}\textrm{Ne}\)
Subtopic: Â Types of Decay |
 65%
From NCERT
NEET - 2022
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NEET 2023 - Target Batch - Aryan Raj Singh
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NEET 2023 - Target Batch - Aryan Raj Singh
A radioactive nucleus \(_{\mathrm{Z}}^{\mathrm{A}}\mathrm{X}\) undergoes spontaneous decay in the sequence \(_{\mathrm{Z}}^{\mathrm{A}}\mathrm{X}\rightarrow \mathrm{B}_{\mathrm{Z-1}}\rightarrow \mathrm{C}_{\mathrm{Z-3}}\rightarrow \mathrm{D}_{\mathrm{Z-2}}\) where \(\mathrm{Z}\) is the atomic number of element \(\mathrm{X}\). The possible decay particles in the sequence are:
| 1. | \(\beta^{+}, ~\alpha, ~\beta^{-}\) | 2. | \(\beta^{-}, ~\alpha, ~\beta^{+}\) |
| 3. | \(\alpha, ~\beta^{-},~\beta^{+}\) | 4. | \(\alpha, ~\beta^{+},~\beta^{-}\) |
Subtopic: Â Types of Decay |
 70%
From NCERT
NEET - 2021
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NEET 2023 - Target Batch - Aryan Raj Singh
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Links
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NEET 2023 - Target Batch - Aryan Raj Singh
What happens to the mass number and the atomic number of an element when it emits \(\gamma\text{-}\)radiation?
| 1. | mass number decreases by four and atomic number decreases by two. |
| 2. | mass number and atomic number remain unchanged. |
| 3. | mass number remains unchanged while the atomic number decreases by one. |
| 4. | mass number increases by four and the atomic number increases by two. |
Subtopic: Â Types of Decay |
 83%
From NCERT
NEET - 2020
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
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NEET 2023 - Target Batch - Aryan Raj Singh
- 1(current)
Q. No.
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