A particle is dropped from a height $$H.$$ The de-Broglie wavelength of the particle as a function of height is proportional to:
1. $$H$$
2. $$H^{1/2}$$
3. $$H^{0}$$
4. $$H^{-1/2}$$

Subtopic:  De-broglie Wavelength |
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The wavelength of a photon needed to remove a proton from a nucleus which is bound to the nucleus with 1 MeV energy is nearly

1. 1.2 nm

2.

3.

4.

Subtopic:  De-broglie Wavelength |
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Consider a beam of electrons (each electron with energy E0) incident on a metal surface kept in an evacuated chamber. Then:

 1 no electrons will be emitted as only photons can emit electrons. 2 electrons can be emitted but all with energy, ${\mathrm{E}}_{0.}$ 3 electrons can be emitted with any energy, with a maximum of $$\mathrm{E}_0-\phi$$ ($$\phi$$ is the work function). 4 electrons can be emitted with any energy, with a maximum $$E_0$$
Subtopic:  Electron Emission |
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Consider the figure given below. Suppose the voltage applied to A is increased. The diffracted beam will have the maximum at a value of $\mathrm{\theta }$ that

1. will be larger than the earlier value

2. will be the same as the earlier value

3. will be less than the earlier value

4. will depend on the target

Subtopic:  Davisson & Germer Experiment |
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A particle moves in a closed orbit around the origin, due to a force which is directed towards the origin. The de-Broglie wavelength of the particle varies cyclically between two values  with ${\mathrm{\lambda }}_{1}>{\mathrm{\lambda }}_{2}$. Which of the following statement/s is/are true?

(a) The particle could be moving in a circular orbit with origin as the centre.
(b) The particle could be moving in an elliptic orbit with origin as its focus.
(c) When the de-Broglie wavelength is ${\mathrm{\lambda }}_{1}$, the particle is nearer the origin than when its value is ${\mathrm{\lambda }}_{2}$.
(d) When the de-Broglie wavelength is ${\mathrm{\lambda }}_{2}$, the particle is nearer the origin than when its value is ${\mathrm{\lambda }}_{1}$.

1. (b, d)

2. (a, c)

3. (b, c, d)

4. (a, c, d)

Subtopic:  De-broglie Wavelength |
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Photons absorbed in matter are converted to heat. A source emitting n photon/sec of frequency $\mathrm{\nu }$ is used to convert 1 kg of ice at $0°\mathrm{C}$ to water at $0°\mathrm{C}$. Then, the time T taken for the conversion:

(a) decreases with increasing n, with $\mathrm{\nu }$ fixed
(b) decreases with n fixed, $\mathrm{\nu }$ increasing
(c) remains constant with n and $\mathrm{\nu }$ changing such that n$\mathrm{\nu }$=constant
(d) increases when the product n$\mathrm{\nu }$ increases

1. (b, d)
2. (a, c, d)
3. (a, d)
4. (a, b, c)

Subtopic:  Particle Nature of Light |
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The de-Broglie wavelength of a photon is twice the de-Broglie wavelength of an electron. The speed of the electron is ${\mathrm{v}}_{\mathrm{e}}=\frac{\mathrm{c}}{100}$. Then,

1. $$\frac{E_e}{E_p}=10^{-4}$$

2. $$\frac{E_e}{E_p}=10^{-2}$$

3. $$\frac{P_e}{m_ec}=10^{-2}$$

4. $$\frac{P_e}{m_ec}=10^{-4}$$

Subtopic:  De-broglie Wavelength |
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Two particles A1 and A2 of masses m1, m2 (m1>m2) have the same de-Broglie wavelength. Then,

(a) their momenta are the same
(b) their energies are the same
(c) energy of A1 is less than the energy of A2
(d) energy of A1 is more than the energy of A2

1. (b, c)
2. (a, c)
3. (c, d)
4. (b, d)

Subtopic:  De-broglie Wavelength |
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Relativistic corrections become necessary when the expression for the kinetic energy $\frac{1}{2}{\mathrm{mv}}^{2}$, becomes comparable with ${\mathrm{mc}}^{2}$, where m is the mass of the particle. At what de-Broglie wavelength, will relativistic corrections become important for an electron?

(a)
(b)
(c)
(d)

1. (a, c)

2. (a, d)

3. (c, d)

4. (a, b)

Subtopic:  De-broglie Wavelength |
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An electron (mass m) with an initial velocity $\stackrel{\to }{\mathrm{v}}={\mathrm{v}}_{0}\stackrel{^}{\mathrm{i}}$ is in an electric field $\stackrel{\to }{\mathrm{E}}={\mathrm{E}}_{0}\stackrel{^}{\mathrm{j}}$. If ${\mathrm{\lambda }}_{0}=\frac{\mathrm{h}}{{\mathrm{mv}}_{0}}$, its de-Broglie wavelength at time t is given by:

1. ${\mathrm{\lambda }}_{0}$

2. ${\mathrm{\lambda }}_{0}\sqrt{1+\frac{{\mathrm{e}}^{2}{\mathrm{E}}_{0}^{2}{\mathrm{t}}^{2}}{{\mathrm{m}}^{2}{\mathrm{v}}_{0}^{2}}}$

3. $\frac{{\mathrm{\lambda }}_{0}}{\sqrt{1+\frac{{\mathrm{e}}^{2}{\mathrm{E}}_{0}^{2}{\mathrm{t}}^{2}}{{\mathrm{m}}^{2}{\mathrm{v}}_{0}^{2}}}}$

4. $\frac{{\mathrm{\lambda }}_{0}}{\left(1+\frac{{\mathrm{e}}^{2}{\mathrm{E}}_{0}^{2}{\mathrm{t}}^{2}}{{\mathrm{m}}^{2}{\mathrm{v}}_{0}^{2}}\right)}$

Subtopic:  De-broglie Wavelength |
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