Q. No.A photon of energy \(3.4~\text{eV}\) is incident on a metal having a work function of \(2~\text{eV}.\) The maximum \(K.E\) of photo-electrons is equal to:
| 1. | \(1.4~\text{eV}\) | 2. | \(1.7~\text{eV}\) |
| 3. | \(5.4~\text{eV}\) | 4. | \(6.8~\text{eV}\) |
Subtopic: Einstein's Photoelectric Equation |
91%
From NCERT
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For photoelectric emission from certain metals, the cutoff frequency is \(\nu.\) If radiation of frequency \(2\nu\) impinges on the metal plate, the maximum possible velocity of the emitted electron will be:
(\(m\) is the electron mass)
| 1. | \(\sqrt{\dfrac{h\nu}{m}}\) | 2. | \(\sqrt{\dfrac{2h\nu}{m}}\) |
| 3. | \(2\sqrt{\dfrac{h\nu}{m}}\) | 4. | \(\sqrt{\dfrac{h\nu}{2m}}\) |
Subtopic: Einstein's Photoelectric Equation |
84%
From NCERT
AIPMT - 2013
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The work function of a metal surface is \(\phi = 1.5\) eV. If a light of wavelength \(5000~\mathring{A}\) falls on it, then the maximum K.E of the ejected electron will be:
| 1. | \(1.2\) eV | 2. | \(0.98\) eV |
| 3. | \(0.45\) eV | 4. | \(0\) eV |
Subtopic: Einstein's Photoelectric Equation |
82%
From NCERT
AIPMT - 1998
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When monochromatic photons of wavelength \(4000~\mathring{A}\) are incident on the metal plate of work function \(2.1~\text{eV},\) what will be the stopping potential for the photocurrent?
| 1. | \(1~\text V\) | 2. | \(2.1~\text V\) |
| 3. | \(3.1~\text V\) | 4. | Zero |
Subtopic: Einstein's Photoelectric Equation |
81%
From NCERT
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The correct graph between the maximum energy of a photoelectron \(\left(K_{max}\right)\) and the inverse of the wavelength \(\left(\frac{1}{\lambda}\right)\) of the incident radiation is given by the curve:
| 1. | \(A\) | 2. | \(B\) |
| 3. | \(C\) | 4. | None of these |
Subtopic: Einstein's Photoelectric Equation |
81%
From NCERT
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A certain metallic surface is illuminated with monochromatic light of wavelength \(\lambda\). The stopping potential for photoelectric current for this light is \(3V_0\). If the same surface is illuminated with light of wavelength \(2\lambda\), the stopping potential is \(V_0\). The photoelectric effect's threshold wavelength for this surface is?
1. \(6\lambda\)
2. \(4\lambda\)
3. \(\dfrac{\lambda}{4}\)
4. \(\dfrac{\lambda}{6}\)
1. \(6\lambda\)
2. \(4\lambda\)
3. \(\dfrac{\lambda}{4}\)
4. \(\dfrac{\lambda}{6}\)
Subtopic: Einstein's Photoelectric Equation |
77%
From NCERT
NEET - 2015
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The work function of a metal surface is \(2\) eV. When the light of frequency \(f\) is incident on the surface, the maximum kinetic energy of the photoelectrons emitted is \(5\) eV. If the frequency of the incident light is increased to \(4f\), then the maximum kinetic energy of the photoelectron emitted will be:
1. \(20\) eV
2. \(22\) eV
3. \(26\) eV
4. \(28\) eV
1. \(20\) eV
2. \(22\) eV
3. \(26\) eV
4. \(28\) eV
Subtopic: Einstein's Photoelectric Equation |
74%
From NCERT
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The work functions for metals \(A,B,\) and \(C\) are respectively \(1.92\) eV, \(2.0\) eV, and \(5\) eV. According to Einstein's equation, the metals that will emit photoelectrons for a radiation of wavelength \(4100~\mathring{A}\) is/are:
1. None
2. \(A\) only
3. \(A\) and \(B\) only
4. All the three metals
Subtopic: Einstein's Photoelectric Equation |
80%
From NCERT
AIPMT - 2005
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The variation of the kinetic energy \((K)\) of photoelectrons as a function of the frequency \((f)\) of the incident radiation is best shown by:
| 1. |  |
2. |  |
| 3. |  |
4. |  |
Subtopic: Einstein's Photoelectric Equation |
73%
From NCERT
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A metallic surface is exposed to two radiations separately, one of wavelength \(4000~\mathring{A}\) and the other of \(8000~\mathring{A}\). If the work function of metal is \(1\) eV, then the ratio of maximum kinetic energies of photoelectrons is nearly equal to:
| 1. | \(\dfrac{32}{11} \) | 2. | \(\dfrac{42}{11} \) |
| 3. | \(\dfrac{52}{11} \) | 4. | \(\dfrac{62}{11}\) |
Subtopic: Einstein's Photoelectric Equation |
76%
From NCERT
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