The curves (1), (2), (3) and (4) show the variation between the applied potential difference (V) and the photoelectric current (i), at two different intensities of light ( ). In which figure is the correct variation shown?
The value of stopping potential in the following diagram is given by:
1. – 4 V
2. – 3 V
3. – 2 V
4. – 1 V
|1.||Curves a and b represent incident radiations of different frequencies and different intensities.|
|2.||Curves a and b represent incident radiation of the same frequency but of different intensities.|
|3.||Curves b and c represent incident radiation of different frequencies and different intensities.|
|4.||Curves b and c represent incident radiations of same frequency having the same intensity.|
When monochromatic radiation of intensity I falls on a metal surface, the number of photoelectrons and their maximum kinetic energy are N and T respectively. If the intensity of radiation is 2I what is the number of emitted electrons and their maximum kinetic energy?
1. N and 2T
2. 2N and T
3. 2N and 2T
4. N and T
The figure shows different graphs between stopping potential and frequency (\(\nu\)) for the photosensitive surfaces of cesium, potassium, sodium and lithium. The plots are parallel.
The correct ranking of the targets according to their work function first will be:
1. (i) > (ii) > (iii) > (iv)
2. (i) > (iii) > (ii) > (iv)
3. (iv) > (iii) > (ii) > (i)
4. (i) = (iii) > (ii) = (iv)
The number of photo-electrons emitted per second from a metal surface increases when:
1. The energy of incident photons increases.
2. The frequency of incident light increases.
3. The wavelength of the incident light increases.
4. The intensity of the incident light increases.
For a photoelectric cell, the graph showing the variation of the cut of voltage (Vo ) with frequency (v) of incident light is best represented by:
Which is the correct curve between the stopping potential (V0) and the intensity of incident light (I)?
The graph between the intensity of light falling on a metallic plate (I) and the generated current (i) is given by:
If in a photoelectric experiment, the wavelength of incident radiation is reduced from 6000 Å to 4000 Å, then:
1. The stopping potential will decrease.
2. The stopping potential will increase.
3. The kinetic energy of emitted electrons will decrease.
4. The value of the work function will decrease.