Consider a ray of light incident from the air onto a slab of glass (refractive index n) of width d, at an angle θ. The phase difference between the ray reflected by the top surface of the glass and the bottom surface is:

1. \(\frac{4 \pi d}{\lambda}\left(1-\frac{1}{n^2} \sin ^2 \theta\right)^{1 / 2}+\pi\)

2. \(\frac{4 \pi d}{\lambda}\left(1-\frac{1}{n^2} \sin ^2 \theta\right)^{1 / 2}\)

3. \(\frac{4 \pi d}{\lambda}\left(1-\frac{1}{n^2} \sin ^2 \theta\right)^{1 / 2}+\frac{\pi}{2}\)

4. \(\frac{4 \pi d}{\lambda}\left(1-\frac{1}{n^2} \sin ^2 \theta\right)^{1 / 2}+2\pi\)

Subtopic:  Superposition Principle |
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Two Sources S1 and S2 of intensity I1 and l2 are in front of a screen [Fig.(a)]. The pattern of intensity distribution seen in the central portion is given by Fig.(b).

            

In this case, which of the following statements are true?

(a) S1and S2 have the same intensities
(b) S1and S2 have a constant phase difference
(c) S1and S2 have the same phase
(d) S1and S2 have the same wavelength 

1. (a, b, c)

2. (a, b, d)

3. (b, c, d)

4. (c, d)

Subtopic:  Superposition Principle |
 53%
From NCERT
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NEET 2023 - Target Batch - Aryan Raj Singh