- 1(current)
Q. No.A person can see clearly objects only when they lie between \(50~\text{cm}\) and \(400~\text{cm}\) from his eyes. In order to increase the maximum distance of distinct vision to infinity, the type and power of the correcting lens, the person has to use will be:
| 1. | \(\text{convex, +2.25 diopter}\) | 2. | \(\text{concave, -0.25 diopter}\) |
| 3. | \(\text{concave, -0.2 diopter}\) | 4. | \(\text{convex, +0.5 diopter}\) |
A man with hypermetropia cannot see objects closer than a distance of \(40~\text{cm}\) from the eye. The power of the lens required so that he can see objects at \(25~\text{cm}\) from the eye is:
1. \(+4.5~\text{D}\)
2. \(+4.0~\text{D}\)
3. \(+1.5~\text{D}\)
4. \(+3.0~\text{D}\)
The near point of a person is \(50~\text{cm}\) and the far point is \(1.5~\text{m}.\) The spectacles required for reading purposes and for seeing distant objects are respectively:
| 1. | \(+2\text{D}, -\frac{2}{3}~\text{D}\) |
| 2. | \( +\frac{2}{3}~\text{D},-2\text{D}\) |
| 3. | \(-2\text{D}, -\frac{2}{3}~\text{D}\) |
| 4. | \( -\frac{2}{3}~\text{D},+2\text{D}\) |
A boy with defective eye-sight cannot see things beyond 50 cm. The corrective lens required has the power:
1. +1 D
2. +2 D
3. -1 D
4. -2 D
A person can see objects clearly between \(1~\text{m} \)and \(3~\text{m}. \). The power of the lens required to correct near point will be:
1. \(-2.5~\text{D}\)
2. \(3~\text{D}\)
3. \(+ 1.5~\text{D}\)
4. \(-
1.75~\text{D}\)
If there had been one eye of a man, then:
| 1. | image of the object would have been inverted |
| 2. | visible region would have decreased |
| 3. | image would have not been seen in three dimensional |
| 4. | Both (2) and (3) |
The diameter of the eye-ball of a normal eye is about 2.5 cm. The power of the eye lens varies from:
1. 2 D to 10 D
2. 40 D to 32 D
3. 9 D to 8 D
4. 44 D to 40 D
- 1(current)
Q. No.
© 2025 GoodEd Technologies Pvt. Ltd.