Instantaneous displacement current of 2.0 A is set up in the space between two parallel plates of \(1~\mu F\)$$ capacitor. The rate of change in potential difference across the capacitor is:

1. $3\times {10}^6$ $V/s$

2. $4\times {10}^6$ $V/s$

3. $2\times {10}^6$ $V/s$

4. None of these

The S.I. unit of displacement current is:
1. Henry
2. Coulomb
3. Ampere
4. Farad

A capacitor is having a capacity of 2 pF. The electric potential across the capacitor is changing with a value of \(10^{12}~\mathrm{V/s}\). The displacement current is:

A variable frequency AC source is connected to a capacitor. Then on increasing the frequency:

The charge of a parallel plate capacitor is varying as $q=q_0\sin \omega t$. Find the magnitude of displacement current through the capacitor. 
(Plate Area = A, separation of plates = d)

1. $q_0\cos \left(\omega t\right)$

2. $q_0\omega \sin \omega t$

3. $q_0\omega \cos \omega t$

4. $\frac{q_{0}A\omega }{d}\cos \omega t$

A larger parallel plate capacitor, whose plates have an area of 1 $m^2$, separated from each other by 1 mm, is being charged at a rate of 25.8 V/s. If the plates have dielectric constant 10, then the displacement current at this instant is:

1. 25 $\mu A$

2. 11 $\mu A$

3. 2.2 $\mu A$

4. 1.1 $\mu A$