Q. No.The electric field in a plane electromagnetic wave is given by \(E_z=60\cos(5x+1.5\times10^9t)~\text{V/m}.\) Then expression for the corresponding magnetic field is (here subscripts denote the direction of the field):
| 1. | \(B_z=60\cos(5x+1.5\times10^9t)~\text T\) |
| 2. | \(B_y=60\sin(5x+1.5\times10^9t)~\text T\) |
| 3. | \(B_y=2\times10^{-7}\cos(5x+1.5\times10^9t)~\text T\) |
| 4. | \(B_x=2\times10^{-7}\cos(5x+1.5\times10^9t)~\text T\) |
Subtopic: Properties of EM Waves |
56%
From NCERT
NEET - 2025
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The property which is not of an electromagnetic wave travelling in free space is that:
| 1. | the energy density in electric field is equal to energy density in magnetic field. |
| 2. | they travel with a speed equal to \(\dfrac{1}{\sqrt{\mu_0~ \varepsilon_0}} .\) |
| 3. | they originate from charges moving with uniform speed. |
| 4. | they are transverse in nature. |
Subtopic: Properties of EM Waves |
68%
From NCERT
NEET - 2024
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If \(\vec{E}\) and \(\vec{B}\) represent the electric field vector and magnetic field vector, respectively, in an electromagnetic wave then the direction of EM wave is along:
| 1. | \(\vec{E}\) | 2. | \(\vec{B}\) |
| 3. | \(\vec{E}\times\vec{B}\) | 4. | \(\vec{B}\times\vec{E}\) |
Subtopic: Properties of EM Waves |
92%
From NCERT
NEET - 2024
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If the ratio of relative permeability and relative permittivity of a uniform medium is \(1 : 4.\) The ratio of the magnitudes of electric field intensity \((E)\) to the magnetic field intensity \((H)\) of an EM wave propagating in that medium is:
\(\left(\text{Given that}\sqrt{\frac{\mu_0}{\varepsilon_0}}=120\pi\right)\)
1. \(30\pi:1\)
2. \(1:120\pi\)
3. \(60\pi:1\)
4. \(120\pi:1\)
\(\left(\text{Given that}\sqrt{\frac{\mu_0}{\varepsilon_0}}=120\pi\right)\)
1. \(30\pi:1\)
2. \(1:120\pi\)
3. \(60\pi:1\)
4. \(120\pi:1\)
Subtopic: Properties of EM Waves |
From NCERT
NEET - 2024
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In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of \(2.0\times 10^{10}~ \text{Hz}\) and amplitude \(48~\text{Vm}^{-1}\). Then the amplitude of the oscillating magnetic field is: (Speed of light in free space \(3\times 10^{8}~ \text{ms}^{-1}\))
1. \(1.6 \times 10^{-6} ~\text{T}\)
2. \(1.6 \times 10^{-9} ~\text{T}\)
3. \(1.6 \times 10^{-8} ~\text{T}\)
4. \(1.6 \times 10^{-7} ~\text{T}\)
1. \(1.6 \times 10^{-6} ~\text{T}\)
2. \(1.6 \times 10^{-9} ~\text{T}\)
3. \(1.6 \times 10^{-8} ~\text{T}\)
4. \(1.6 \times 10^{-7} ~\text{T}\)
Subtopic: Properties of EM Waves |
64%
From NCERT
NEET - 2023
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\(\varepsilon_0\) and \(\mu_0\) are the electric permittivity and magnetic permeability of free space respectively. If the corresponding quantities of a medium are \(2\varepsilon_0\) and \(1.5\mu_0\) respectively, the refractive index of the medium will nearly be:
1. \(\sqrt2\)
2. \(\sqrt3\)
3. \(3\)
4. \(2\)
1. \(\sqrt2\)
2. \(\sqrt3\)
3. \(3\)
4. \(2\)
Subtopic: Properties of EM Waves |
81%
From NCERT
NEET - 2023
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When light propagates through a material medium of relative permittivity, \(\varepsilon_{r}\) and relative permeability, \(\mu_{r}\) the velocity of light, \(v\) is given by:
(\(c\) = velocity of light in vacuum)
1. \(v=\dfrac{{c}}{\sqrt{\varepsilon_{r} \mu_{{r}}}}\)
2. \(v={c}\)
3. \(v=\sqrt{\dfrac{\mu_{{r}}}{\varepsilon_{{r}}}}\)
4. \(v=\sqrt{\dfrac{\varepsilon_{{r}}}{\mu_{{r}}}}\)
(\(c\) = velocity of light in vacuum)
1. \(v=\dfrac{{c}}{\sqrt{\varepsilon_{r} \mu_{{r}}}}\)
2. \(v={c}\)
3. \(v=\sqrt{\dfrac{\mu_{{r}}}{\varepsilon_{{r}}}}\)
4. \(v=\sqrt{\dfrac{\varepsilon_{{r}}}{\mu_{{r}}}}\)
Subtopic: Properties of EM Waves |
86%
From NCERT
NEET - 2022
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An electromagnetic wave is moving along negative \(z (-z)\) direction and at any instant of time, at a point, its electric field vector is \(3\hat j~\text{V/m}\). The corresponding magnetic field at that point and instant will be: (Take \(c=3\times10^{8}~\text{ms}^{-1}\))
| 1. | \(10\hat i~\text{nT}\) | 2. | \(-10\hat i~\text{nT}\) |
| 3. | \(\hat i~\text{nT}\) | 4. | \(-\hat i~\text{nT}\) |
Subtopic: Properties of EM Waves |
56%
From NCERT
NEET - 2022
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The magnetic field of a plane electromagnetic wave
is given by,
\(\vec B=3\times10^{-8}\text{cos}(1.6\times10^3x+48\times10^{10}t)\hat j~\text{T}.\)
The associated electric field will be:
is given by,
\(\vec B=3\times10^{-8}\text{cos}(1.6\times10^3x+48\times10^{10}t)\hat j~\text{T}.\)
The associated electric field will be:
| 1. | \(3 \times 10^{-8} \text{cos}\left(1.6 \times 10^3 x+48 \times 10^{10} t\right) \hat{i}~\text{ V/m}\) |
| 2. | \(3 \times 10^{-8} \text{sin} \left(1.6 \times 10^3 {x}+48 \times 10^{10} {t}\right) \hat{{i}}~ \text{V} / \text{m}\) |
| 3. | \(9 \text{sin} \left(1.6 \times 10^3 {x}-48 \times 10^{10} {t}\right) \hat{{k}} ~~\text{V} / \text{m}\) |
| 4. | \(9 \text{cos} \left(1.6 \times 10^3 {x}+48 \times 10^{10} {t}\right) \hat{{k}}~~\text{V} / \text{m}\) |
Subtopic: Properties of EM Waves |
59%
From NCERT
NEET - 2022
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The ratio of the magnitude of the magnetic field and electric field intensity of a plane electromagnetic wave in free space of permeability \(\mu_0\) and permittivity \(\varepsilon_0\) is:
(Given that \(c=\) velocity of light in free space)
1. \(c\)
2. \(\dfrac1c\)
3. \(\dfrac{c}{\sqrt{\mu_0\varepsilon_0}}\)
4. \(\dfrac{\sqrt{\mu_0\varepsilon_0}}{c}\)
(Given that \(c=\) velocity of light in free space)
1. \(c\)
2. \(\dfrac1c\)
3. \(\dfrac{c}{\sqrt{\mu_0\varepsilon_0}}\)
4. \(\dfrac{\sqrt{\mu_0\varepsilon_0}}{c}\)
Subtopic: Properties of EM Waves |
61%
From NCERT
NEET - 2022
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