Q. No.In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of \(2.0\times 10^{10}~ \text{Hz}\) and amplitude \(48~\text{Vm}^{-1}\). Then the amplitude of the oscillating magnetic field is: (Speed of light in free space \(3\times 10^{8}~ \text{ms}^{-1}\))
1. \(1.6 \times 10^{-6} ~\text{T}\)
2. \(1.6 \times 10^{-9} ~\text{T}\)
3. \(1.6 \times 10^{-8} ~\text{T}\)
4. \(1.6 \times 10^{-7} ~\text{T}\)
1. \(1.6 \times 10^{-6} ~\text{T}\)
2. \(1.6 \times 10^{-9} ~\text{T}\)
3. \(1.6 \times 10^{-8} ~\text{T}\)
4. \(1.6 \times 10^{-7} ~\text{T}\)
Subtopic: Â Properties of EM Waves |
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NEET - 2023
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\(\varepsilon_0\) and \(\mu_0\) are the electric permittivity and magnetic permeability of free space respectively. If the corresponding quantities of a medium are \(2\varepsilon_0\) and \(1.5\mu_0\) respectively, the refractive index of the medium will nearly be:
1. \(\sqrt2\)
2. \(\sqrt3\)
3. \(3\)
4. \(2\)
1. \(\sqrt2\)
2. \(\sqrt3\)
3. \(3\)
4. \(2\)
Subtopic: Â Properties of EM Waves |
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NEET - 2023
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When light propagates through a material medium of relative permittivity, \(\epsilon_{r}\) and relative permeability, \(\mu_{r}\) the velocity of light, \(v\) is given by:
(\(c\) = velocity of light in vacuum)
1. \(v=\frac{{c}}{\sqrt{\epsilon_{r} \mu_{{r}}}}\)
2. \(v={c}\)
3. \(v=\sqrt{\frac{\mu_{{r}}}{\epsilon_{{r}}}}\)
4. \(v=\sqrt{\frac{\epsilon_{{r}}}{\mu_{{r}}}}\)
(\(c\) = velocity of light in vacuum)
1. \(v=\frac{{c}}{\sqrt{\epsilon_{r} \mu_{{r}}}}\)
2. \(v={c}\)
3. \(v=\sqrt{\frac{\mu_{{r}}}{\epsilon_{{r}}}}\)
4. \(v=\sqrt{\frac{\epsilon_{{r}}}{\mu_{{r}}}}\)
Subtopic: Â Properties of EM Waves |
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An electromagnetic wave is moving along negative \(\text{z (-z)}\) direction and at any instant of time, at a point, its electric field vector is \(3\hat j~\text{V/m}\). The corresponding magnetic field at that point and instant will be: (Take \(c=3\times10^{8}~\text{ms}^{-1}\) )
| 1. | \(10\hat i~\text{nT}\) | 2. | \(-10\hat i~\text{nT}\) |
| 3. | \(\hat i~\text{nT}\) | 4. | \(-\hat i~\text{nT}\) |
Subtopic: Â Properties of EM Waves |
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The magnetic field of a plane electromagnetic wave
is given by,
\(\vec B=3\times10^{-8}\text{cos}(1.6\times10^3x+48\times10^{10}t)\hat j~\text{T}.\)
The associated electric field will be:
is given by,
\(\vec B=3\times10^{-8}\text{cos}(1.6\times10^3x+48\times10^{10}t)\hat j~\text{T}.\)
The associated electric field will be:
| 1. | \(3 \times 10^{-8} \text{cos}\left(1.6 \times 10^3 x+48 \times 10^{10} t\right) \hat{i}~\text{ V/m}\) |
| 2. | \(3 \times 10^{-8} \text{sin} \left(1.6 \times 10^3 {x}+48 \times 10^{10} {t}\right) \hat{{i}}~ \text{V} / \text{m}\) |
| 3. | \(9 \text{sin} \left(1.6 \times 10^3 {x}-48 \times 10^{10} {t}\right) \hat{{k}} ~~\text{V} / \text{m}\) |
| 4. | \(9 \text{cos} \left(1.6 \times 10^3 {x}+48 \times 10^{10} {t}\right) \hat{{k}}~~\text{V} / \text{m}\) |
Subtopic: Â Properties of EM Waves |
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The ratio of the magnitude of the magnetic field and electric field intensity of a plane electromagnetic wave in free space of permeability \(\mu_0\) and permittivity \(\varepsilon_0\) is:
(Given that \(c=\) velocity of light in free space)
1. \(c\)
2. \(\frac1c\)
3. \(\frac{c}{\sqrt{\mu_0\varepsilon_0}}\)
4. \(\frac{\sqrt{\mu_0\varepsilon_0}}{c}\)
(Given that \(c=\) velocity of light in free space)
1. \(c\)
2. \(\frac1c\)
3. \(\frac{c}{\sqrt{\mu_0\varepsilon_0}}\)
4. \(\frac{\sqrt{\mu_0\varepsilon_0}}{c}\)
Subtopic: Â Properties of EM Waves |
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For a plane electromagnetic wave propagating in the \(x\)-direction, which one of the following combinations gives the correct possible directions for the electric field \((E)\) and magnetic field \((B)\) respectively?
1. \(\hat{j}+\hat{k},~-\hat{j}-\hat{k}\)
2. \(-\hat{j}+\hat{k},~-\hat{j}+\hat{k}\)
3. \(\hat{j}+\hat{k},~\hat{j}+\hat{k}\)
4. \(-\hat{j}+\hat{k},~-\hat{j}-\hat{k}\)
1. \(\hat{j}+\hat{k},~-\hat{j}-\hat{k}\)
2. \(-\hat{j}+\hat{k},~-\hat{j}+\hat{k}\)
3. \(\hat{j}+\hat{k},~\hat{j}+\hat{k}\)
4. \(-\hat{j}+\hat{k},~-\hat{j}-\hat{k}\)
Subtopic: Â Properties of EM Waves |
From NCERT
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The ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic wave is: (\(c\) = speed of electromagnetic waves)
| 1. | \(1:1\) | 2. | \(1:c\) |
| 3. | \(1:c^2\) | 4. | \(c:1\) |
Subtopic: Â Properties of EM Waves |
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Light with an average flux of \(20~\text{W/cm}^2\) falls on a non-reflecting surface at normal incidence having a surface area \(20~\text{cm}^2\). The energy received by the surface during time span of \(1\) minute is:
1. \(12\times 10^{3}~\text{J}\)
2. \(24\times 10^{3}~\text{J}\)
3. \(48\times 10^{3}~\text{J}\)
4. \(10\times 10^{3}~\text{J}\)
Subtopic: Â Properties of EM Waves |
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The magnetic field in a plane electromagnetic wave is given by:
\(B_y = 2\times10^{-7} \text{sin}\left(\pi \times10^{3}x+3\pi\times10^{11}t\right )T\)
The wavelength is:
1. \(\pi\times 10^{3}~\text{m}\)
2. \(2\times10^{-3}~\text{m}\)
3. \(2\times10^{3}~\text{m}\)
4. \(\pi\times 10^{-3}~\text{m}\)
Subtopic: Â Properties of EM Waves |
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From NCERT
NEET - 2020
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