# A big circular coil of $$1000$$ turns and average radius $$10~\text{m}$$ is rotating about its horizontal diameter at $$2~\text{rad s}^{-1}$$. If the vertical component of earth's magnetic field at that place is $$2\times 10^{-5}~\text{T}$$ and electrical resistance of the coil is $$12.56~\Omega,$$ then the maximum induced current in the coil will be: 1. $$2~\text{A}$$ 2. $$0.25~\text{A}$$ 3. $$1.5~\text{A}$$ 4. $$1~\text{A}$$

Subtopic: Â Faraday's Law & Lenz Law |
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The current in an inductor of self-inductance $$4~\text{H}$$ changes from $$4~ \text{A}$$ to $$2~\text{A}$$ in $$1~ \text s$$. The emf induced in the coil is:
1. $$-2~\text{V}$$
2. $$2~\text{V}$$
3. $$-4~\text{V}$$
4. $$8~\text{V}$$

Subtopic: Â Self - Inductance |
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NEET - 2022
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The dimensions of mutual inductance $$(M)$$ are:
1. $$\left[M^2LT^{-2}A^{-2}\right]$$
2. $$\left[MLT^{-2}A^{2}\right]$$
3. $$\left[M^{2}L^{2}T^{-2}A^{2}\right]$$
4. $$\left[ML^{2}T^{-2}A^{-2}\right]$$

Subtopic: Â Mutual Inductance |
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NEET - 2022
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The magnetic field, through a closed loop of conducting wire covering an area of $$100$$ cm2, is $$5\times10^{-2}$$ T and it is uniform and normal to the area. If the field is switched off in a time of $$10$$ ms, the average emf induced is:
 1 $$5$$ V 2 $$0.5$$ V 3 $$0.05$$ V 4 $$5\times10^{-4}$$ V
Subtopic: Â Faraday's Law & Lenz Law |
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A straight horizontal wire $$\mathrm{AB}$$ of length $$l$$ falls from rest under gravity. A uniform horizontal magnetic field $$B$$ acts perpendicular to the plane of motion of $$\mathrm{AB}$$, as shown. The induced emf across $$\mathrm{AB}$$, $$E$$, is proportional to:

 1 $$B$$ 2 $$l$$ 3 time, $$t$$ 4 all of the above
Subtopic: Â Motional emf |
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A square loop of side $$1$$ m and resistance $$1$$ $$\Omega$$ is placed in a magnetic field of $$0.5$$ T. If the plane of the loop is perpendicular to the direction of the magnetic field, the magnetic flux through the loop is:
 1 $$0$$ 2 $$2$$ weber 3 $$0.5$$ weber 4 $$1$$ weber
Subtopic: Â Magnetic Flux |
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NEET - 2022
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An $$L$$-shaped rod $$(ABC;AB=BC=a)$$ moves in its own plane with a velocity $$v$$ parallel to $$AB.$$ There is a uniform magnetic field $$B$$ acting into the plane as shown. The emf developed between $$A,C$$ is:

1. $$Bav$$
2. $$\sqrt2Bav$$
3. $$\frac{Bav}{2}$$
4. zero
Subtopic: Â Motional emf |
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A conducting circular wire of radius $$r$$ is moving with constant velocity $$v$$ towards the right in a uniform magnetic field $$B.$$ We consider two points $$X,Y$$ such that chord $$XY$$ is perpendicular to the velocity $$v$$ and is at a distance $$x$$ from the centre $$(O)$$ of the circle. The EMF induced between $$X,Y$$ is $$\varepsilon.$$ Then, $$\varepsilon$$ is proportional to:

1. $$x$$
2. $$\sqrt{r^2-x^2}$$
3. $$r$$
4. $$x\sqrt{r^2-x^2}$$
Subtopic: Â Motional emf |
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The self-inductance of a long solenoid of cross-section $$A,$$ total length $$L$$ and total number of turns $$N,$$ is (approximately):
 1 $$\dfrac{\mu_0A}{L}\cdot N$$ 2 $$\dfrac{\mu_0A}{L}\cdot N^2$$ 3 $$\dfrac{\mu_0L^3}{A}\cdot N$$ 4 $$\dfrac{\mu_0L^3}{A}\cdot N^2$$
Subtopic: Â Self - Inductance |
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A straight horizontal wire of mass $$m$$ and length $$l,$$ and having a negligible resistance can slide freely on a pair of conducting parallel rails, placed vertically. The rails are connected at the top by a capacitor $$C.$$ A uniform magnetic field $$B$$ exists in the region, perpendicular to the plane of the rails. The wire:

 1 falls with uniform velocity. 2 accelerates down with acceleration less than $$g$$. 3 accelerates down with acceleration equal to  $$g$$. 4 moves down and eventually comes to rest.
Subtopic: Â Motional emf |
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From NCERT