Two coils have a mutual inductance $$0.005$$ H. The current changes in the first coil according to equation $$I=I_{0}\sin\omega t$$ where $$I_{0}=2$$ A and $$\omega=100\pi$$ rad/s. The maximum value of emf in the second coil is:
1. $$4\pi$$ V
2. $$3\pi$$ V
3. $$2\pi$$ V
4. $$\pi$$ V

Subtopic: Â Mutual Inductance |
Â 72%
From NCERT
AIPMT - 1998
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Initially plane of a coil is parallel to the uniform magnetic field $$B$$. If in time $$\Delta t$$ the coil is perpendicular to the magnetic field, then charge flows in $$\Delta t$$ depends on this time as:
1. $$\propto \Delta t$$
2. $$\propto \frac{1}{\Delta t}$$
3. $$\propto (\Delta t)^0$$
4. $$\propto (\Delta t)^{2}$$

Subtopic: Â Motional emf |
Â 77%
From NCERT
AIPMT - 1999
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For an inductor coil, $$L = 0.04 ~\text{H}$$, the work done by a source to establish a current of $$5~\text{A}$$ in it is:
1.  $$0.5~\text{J}$$
2.  $$1.00~\text{J}$$
3.  $$100~\text{J}$$
4.  $$20~\text{J}$$

Subtopic: Â Self - Inductance |
From NCERT
AIPMT - 1999
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For a coil having $$L=2~\text{mH},$$ the current flow through it is $$I=t^2e^{-t}.$$ The time at which emf becomes zero is:
1. $$2$$ s
2. $$1$$ s
3. $$4$$ s
4. $$3$$ s

Subtopic: Â Self - Inductance |
Â 60%
From NCERT
AIPMT - 2001
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The magnetic flux through a circuit of resistance $$R$$ changes by an amount $$\Delta \phi$$ in a time $$\Delta t$$. Then the total quantity of electric charge $$Q$$ that passes any point in the circuit during the time $$\Delta t$$ is represented by:
1. $$Q= \frac{\Delta \phi}{R}$$
2. $$Q= \frac{\Delta \phi}{\Delta t}$$
3. $$Q=R\cdot \frac{\Delta \phi}{\Delta t}$$
4. $$Q=\frac{1}{R}\cdot \frac{\Delta \phi}{\Delta t}$$

Subtopic: Â Faraday's Law & Lenz Law |
Â 83%
From NCERT
AIPMT - 2004
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As a result of a change in the magnetic flux linked to the closed-loop shown in the figure, an emf, $$V$$ volt is induced in the loop. The work done (joules) in taking a charge $$Q$$ coulomb once along the loop is:

 1 $$QV$$ 2 $$\dfrac{QV}{2}$$ 3 $$2QV$$ 4 zero
Subtopic: Â Faraday's Law & Lenz Law |
From NCERT
AIPMT - 2005
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