A thin diamagnetic rod is placed vertically between the poles of an electromagnet. When the current in the electromagnet is switched on, then the diamagnetic rod is pushed up, out of the horizontal magnetic field. Hence the rod gains gravitational potential energy. The work required to do this comes from:

1. | the current source |

2. | the magnetic field |

3. | the lattice structure of the material of the rod |

4. | the induced electric field due to the changing magnetic field. |

Subtopic: Magnetic Materials |

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A 250-turn rectangular coil with a length of 2.1 cm and a width of 1.25 cm carries 85 A and is subjected to a magnetic field with a strength of 0.85 T. What is the work done to rotate the coil by 180 degrees against the torque?

1. 9.1 $\mu J$

2. 4.55 $\mu J$

3. 2.3 $\mu $$J$

4. 1.5 $\mu J$

Subtopic: Analogy between Electrostatics & Magnetostatics |

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If ${\theta}_{1}and{\theta}_{2}$ be the apparent angles of dip observed in two vertical planes at right angles to each other, then the true angle of dip $\theta $ is given by

(1) $co{t}^{2}\theta =co{t}^{2}{\theta}_{1}+co{t}^{2}{\theta}_{2}$

(2) ${\mathrm{tan}}^{2}\theta ={\mathrm{tan}}^{2}{\theta}_{1}+{\mathrm{tan}}^{2}{\theta}_{2}$

(3) $co{t}^{2}\theta =co{t}^{2}{\theta}_{1}-{\mathrm{tan}}^{2}{\theta}_{2}$

(4) ${\mathrm{tan}}^{2}\theta ={\mathrm{tan}}^{2}{\theta}_{1}-{\mathrm{tan}}^{2}{\theta}_{2}$

Subtopic: Earth's Magnetism |

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If ${\theta}_{1}$ and ${\theta}_{2}$ be the apparent angles of dip observed in two vertical planes at right angles to each other, then the true angle of dip $\theta $ is given by:-

1. ${\mathrm{tan}}^{2}\theta ={\mathrm{tan}}^{2}{\theta}_{1}+ta{n}^{2}{\theta}_{2}$

2. $co{t}^{2}\theta =co{t}^{2}{\theta}_{1}-co{t}^{2}{\theta}_{2}$

3. ${\mathrm{tan}}^{2}\theta ={\mathrm{tan}}^{2}{\theta}_{1}+ta{n}^{2}{\theta}_{2}$

4. $co{t}^{2}\theta =co{t}^{2}{\theta}_{1}+co{t}^{2}{\theta}_{2}$

Subtopic: Earth's Magnetism |

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A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in the equilibrium state. The energy required to rotate it by ${60}^{\circ}$ is *W. *Now the torque required to keep the magnet in this new position is:

1. $\frac{W}{\sqrt{3}}$

2. $\sqrt{3}W$

3. $\frac{\sqrt{3}W}{2}$

4. $\frac{2W}{\sqrt{3}}$

Subtopic: Analogy between Electrostatics & Magnetostatics |

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The magnetic susceptibility is negative for

1. paramagnetic material only

2. ferromagnetic material only

3. paramagnetic and ferromagnetic materials

4. diamagnetic material only

Subtopic: Magnetic Materials |

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A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in the equilibrium state. The energy required to rotate it by 60^{o} is W. Now the torque required to keep the magnet in this new position is:

1. $\frac{W}{\sqrt{3}}$

2. $\sqrt{3}W$

3. $\frac{\sqrt{3}W}{2}$

4. $\frac{2W}{\sqrt{3}}$

Subtopic: Analogy between Electrostatics & Magnetostatics |

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The magnetic susceptibility is negative for:

1. Paramagnetic material only

2. Ferromagnetic material only

3. Paramagnetic and ferromagnetic materials

4. Diamagnetic material only

2. Ferromagnetic material only

3. Paramagnetic and ferromagnetic materials

4. Diamagnetic material only

Subtopic: Magnetic Materials |

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