A circular coil of \(16\) turns and a radius of \(10~\text{cm}\) carrying a current of \(0.75~\text{A}\) rests with its plane normal to an external field of magnitude \(5.0\times 10^{-2}~\text{T}\). The coil is free to turn about an axis in its plane perpendicular to the field direction. When the coil is turned slightly and released, it oscillates about its stable equilibrium with a frequency of \(2.0~\text{s}^{-1}\).The moment of inertia of the coil about its axis of rotation is:
1. \(1.39\times 10^{-4}~ \text{kg m}^{2}\)

2. \(2.19\times 10^{-4} ~\text{kg m}^{2}\)
3. \(2.39\times 10^{-4} ~\text{kg m}^{2}\)
 \(1.19\times 10^{-4}~\text{kg m}^{2}\)

Subtopic:  Bar Magnet |
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh