A bar magnet of magnetic moment \(1.5~\text{J/T}\) lies aligned with the direction of a uniform magnetic field of \(0.22~\text{T}\). What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment normal to the field direction?
1. \(0.66\) J
2. \(0.33\) J
3. \(0\)
4. \(0.44\) J
1. | \(0.38~\text{G}\) along the \(\text{N-S}\) direction. |
2. | \(0.48~\text{G}\) along the \(\text{N-S}\) direction. |
3. | \(0.38~\text{G}\) along the \(\text{S-N}\) direction. |
4. | \(0.48~\text{G}\) along the \(\text{S-N}\) direction. |