Select Chapter Topics:

1. | current density | 2. | current |

3. | drift velocity | 4. | electric field |

Subtopic: Current & Current Density |

59%

From NCERT

NEET - 2015

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Two cities are \(150~\text{km}\) apart. Electric power is sent from one city to another city through copper wires. The fall of potential per km is \(8\) volts and the average resistance per km is \(0.5~\text{ohm}\). The power loss in the wire is:

1. \(19.2~\text{W}\)

2. \(19.2~\text{kW}\)

3. \(19.2~\text{J}\)

4. \(12.2~\text{kW}\)

Subtopic: Heating Effects of Current |

82%

From NCERT

AIPMT - 2014

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A wire of resistance \(4~\Omega\) is stretched to twice its original length. The resistance of a stretched wire would be:

1. \(4~\Omega\)

2. \(8~\Omega\)

3. \(16~\Omega\)

4. \(2~\Omega\)

Subtopic: Derivation of Ohm's Law |

82%

From NCERT

AIPMT - 2013

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Internal resistance of a \(2.1~\text{V}\) cell which gives a current of \(0.2~\text{A}\) through a resistance of \(10~\Omega\) is:

1. \(0.5~\Omega\)

2. \(0.8~\Omega\)

3. \(1.0~\Omega\)

4. \(0.2~\Omega\)

1. \(0.5~\Omega\)

2. \(0.8~\Omega\)

3. \(1.0~\Omega\)

4. \(0.2~\Omega\)

Subtopic: EMF & Terminal Voltage |

83%

From NCERT

AIPMT - 2013

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The resistances of the four arms \(P,Q,R~\text{and}~S\) in a Wheatstone’s bridge are \(10~\Omega,30~\Omega,30~\Omega\) and \(90~\Omega\) respectively. The emf and internal resistance of the cell are \(7~\text{volt}\) and \(5~\Omega\) respectively. If the galvanometer resistance is \(50~\Omega\) the current drawn from the cell will be:

1. \(0.2~\text{A}\)

2. \(0.1~\text{A}\)

3. \(2.0~\text{A}\)

4. \(1.0~\text{A}\)

2. \(0.1~\text{A}\)

3. \(2.0~\text{A}\)

4. \(1.0~\text{A}\)

Subtopic: Wheatstone Bridge |

76%

From NCERT

AIPMT - 2013

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If the voltage across a bulb rated \((220~\text{V}\text-100~\text{W})\) drops by \(2.5\%\) of its rated value, the percentage of the rated value by which the power would decrease is:

1. \(20\%\)

2. \(2.5\%\)

3. \(5\%\)

4. \(10\%\)

Subtopic: Heating Effects of Current |

77%

From NCERT

AIPMT - 2012

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A ring is made of a wire having a resistance of \(R_0=12~\Omega.\). Find points \(\mathrm{A}\) and \(\mathrm{B}\), as shown in the figure, at which a current-carrying conductor should be connected so that the resistance \(R\) of the subcircuit between these points equals \(\frac{8}{3}~\Omega\)$\mathrm{?}$

** **

1. \(\frac{l_1}{l_2} = \frac{5}{8}\)

2. \(\frac{l_1}{l_2} = \frac{1}{3}\)

3. \(\frac{l_1}{l_2} = \frac{3}{8}\)

4. \(\frac{l_1}{l_2} = \frac{1}{2}\)

Subtopic: Combination of Resistors |

51%

From NCERT

AIPMT - 2012

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If power dissipated in the \(9~\Omega\) resistor in the circuit shown is \(36\) W, the potential difference across the \(2~\Omega\) resistor will be:

1. \(8\) V

2. \(10\) V

3. \(2\) V

4. \(4\) V

Subtopic: Heating Effects of Current |

78%

From NCERT

AIPMT - 2011

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A current of \(2~\text{A}\) flows through a \(2~\Omega\) resistor when connected across a battery. The same battery supplies a current of \(0.5~\text{A}\) when connected across a \(9~\Omega\) resistor. The internal resistance of the battery is:

1. \(\frac{1}{3}~\Omega\)

2. \(\frac{1}{4}~\Omega\)

3. \(1~\Omega\)

4. \(0.5~\Omega\)

Subtopic: EMF & Terminal Voltage |

78%

From NCERT

AIPMT - 2011

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Given below two statements:

Statement I: |
Kirchhoff’s junction law follows the conservation of charge. |

Statement II: |
Kirchhoff’s loop law follows the conservation of energy. |

1. | Both Statement I and Statement II are incorrect. |

2. | Statement I is correct but Statement II is incorrect. |

3. | Statement I is incorrect and Statement II is correct. |

4. | Both Statement I and Statement II are correct. |

Subtopic: Kirchoff's Voltage Law |

82%

From NCERT

AIPMT - 2010

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Select Chapter Topics: