In the circuit shown in the figure below, the current supplied by the battery is:

                                     

1.  2 A

2.  1 A

3.  0.5 A

4.  0.4 A

The figure below shows a network of currents. The current \(i\) will be:

1. \(3~\mathrm{A}\)
2. \(13~\mathrm{A}\)
3. \(23~\mathrm{A}\)
4. \(-3~\mathrm{A}\)

A battery of internal resistance r, when connected across \(2~\Omega\) resistor supplies a current of 4 A. When the battery is connected across a \(5~\Omega\) resistor, it supplies a current of 2 A. The value of r is: 

Power consumed in the given circuit is \(P_1\). On interchanging the position of \(3~\Omega\)$$ and \(12~\Omega\)$$ resistances, the new power consumption is \(P_2\). The ratio of \(\frac{P_2}{P_1}\) is:
     

A coil heating a bucket full of water raises the temperature by 5 $°$C in 2 min. lf the current in the coil is doubled, what will be the change in the temperature of water in 1 min? (Assume no loss of heat to the surroundings)

What is the reading of the voltmeter of resistance 1200 $\Omega$ connected in the following circuit diagram? 

1. 2.5 V

2. 5.0 V

3. 7.5 V

4. 40 V

The dependence of resistivity \((\rho)\) on the temperature \((T)\) of a semiconductor is, roughly, represented by:

1.		2.
3.		4.

Current through the \(2~\Omega\)$$ resistance in the electrical network shown is:

Two batteries, one of emf 18V and internal resistance 2 $\mathrm{\Omega }$ and the other of emf 12 V and internal resistance 1 $\mathrm{\Omega ,}$ are connected as shown. Reading of the voltmeter is:
(if voltmeter is ideal)

1.  14 V

2.  15 V

3.  18 V

4.  30 V

The metre bridge shown is in a balanced position with \(\frac{P}{Q} = \frac{l_1}{l_2}\). If we now interchange the position of the galvanometer and the cell, will the bridge work? If yes, what will be the balanced condition?

    
1. Yes, \(\frac{P}{Q}=\frac{l_1-l_2}{l_1+l_2}\)
2. No, no null point
3. Yes, \(\frac{P}{Q}= \frac{l_2}{l_1}\)
4. Yes, \(\frac{P}{Q}= \frac{l_1}{l_2}\)