A battery of internal resistance \(r\), when connected across \(2~\Omega\) resistor supplies a current of \(4~\text{A}\). When the battery is connected across a \(5~\Omega\) resistor, it supplies a current of \(2~\text{A}\). The value of \(r\) is: 

1.	\(2~\Omega\)	2	\(1~\Omega\)
3.	\(0.5~\Omega\)	4.	zero

In the circuit shown in the figure below, the current supplied by the battery is:
 
1. \(2~\text A\) 
2. \(1~\text A\) 
3. \(0.5~\text A\) 
4. \(0.4~\text A\) 

The figure below shows a network of currents. The current \(i\) will be:

           

1. \(3~\text{A}\)
2. \(13~\text{A}\)
3. \(23~\text{A}\)
4. \(-3~\text{A}\)

Power consumed in the given circuit is \(P_1.\) On interchanging the position of \(3~\Omega\)$$ and \(12~\Omega\)$$ resistances, the new power consumption is \(P_2.\) The ratio of \(\dfrac{P_2}{P_1}\) is:

What is the reading of the voltmeter of resistance \(1200~\Omega\) connected in the following circuit diagram? 

The dependence of resistivity \((\rho)\) on the temperature \((T)\) of a semiconductor is, roughly, represented by:

1.		2.
3.		4.

Current through the \(2~\Omega\)$$ resistance in the electrical network shown is:

Two batteries, one of emf \(18~\text{V}\) and internal resistance \(2~\Omega\) and the other of emf \(12~\text V\) and internal resistance \(1~\Omega,\) are connected as shown. Reading of the voltmeter is:
(if a voltmeter is ideal)

1. \(14~\text V\) 
2. \(15~\text V\) 
3. \(18~\text V\) 
4. \(30~\text V\) 

The metre bridge shown is in a balanced position with \(\frac{P}{Q} = \frac{l_1}{l_2}\). If we now interchange the position of the galvanometer and the cell, will the bridge work? If yes, what will be the balanced condition?