The net resistance of the circuit between \(A\) and \(B\) is:

   

1.	\(\frac{8}{3}~\Omega\)	2.	\(\frac{14}{3}~\Omega\)
3.	\(\frac{16}{3}~\Omega\)	4.	\(\frac{22}{3}~\Omega\)

Two batteries, one of emf \(18\) volts and internal resistance \(2~\Omega\) and the other of emf \(12\) V and internal resistance \(1~\Omega,\) are connected as shown. The voltmeter \(\mathrm{V}\) will record a reading of: 

1. \(18\) V
2. \(30\) V
3. \(14\) V
4. \(15\) V

A \(5-\)ampere fuse wire can withstand a maximum power of \(1\) watt in a circuit. The resistance of the fuse wire is:

When a wire of uniform cross-section a, length l, and resistance R is bent into a complete circle, the resistance between any two diametrically opposite points will be:

1. R/2

2. R/4

3. R/8

4. 4R

For the network shown in the figure below, the value of the current i is:

1. $\frac{18\mathrm{V}}{5}$

2. $\frac{5\mathrm{V}}{9}$

3. $\frac{9\mathrm{V}}{35}$

4. $\frac{5\mathrm{V}}{18}$

A car battery of emf \(12~\text{V}\) and internal resistance \(5\times 10^{-2}~\Omega\) receives a current of \(60~\text{A}\) from an external source. The terminal voltage of the battery is:

If there are two bulbs of (\(40~\text{W},200~\text{V}\)), and (\(100~\text{W},200~\text{V}\)), then the correct relation for their resistance is:

When three identical bulbs are connected in series, the consumed power is 10 W. If they are now connected in parallel then the consumed power will be:
1.  30 W
2.  90 W
3.  \(\frac{10}{3}\) W
4.  270 W

According to the Faraday Law of electrolysis, the mass deposited at electrode will be proportional to:

1. m ∝ I²

2. m ∝ Q

3. m ∝ Q²

4. 'm' does not depend on Q

In a hot wire ammeter due to the flowing of the current, the temperature of the wire is increased by 5° C. If the value of the current is doubled, then the increase in temperature will be:
1.  15° C
2.  20° C
3.  25° C
4.  30° C