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Two metal wires of identical dimensions are connected in series. If ${\mathrm{}}_{}$\(\sigma_1\)

1. | \(\frac{2\sigma_1 \sigma_2}{\sigma_1+\sigma_2}\) | 2. | \(\frac{\sigma_1 +\sigma_2}{2\sigma_1\sigma_2}\) |

3. | \(\frac{\sigma_1 +\sigma_2}{\sigma_1\sigma_2}\) | 4. | \(\frac{\sigma_1 \sigma_2}{\sigma_1+\sigma_2}\) |

Subtopic: Derivation of Ohm's Law |

63%

From NCERT

NEET - 2015

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A potentiometer wire of length \(L\) and a resistance \(r\) are connected in series with a battery of EMF \(E_{0 }\) and resistance \(r_{1}\). An unknown EMF is balanced at a length l of the potentiometer wire. The EMF \(E\) will be given by:

1. \(\frac{L E_{0} r}{l r_{1}}\)

2. \(\frac{E_{0} r}{\left(\right. r + r_{1} \left.\right)} \cdot \frac{l}{L}\)

3. \(\frac{E_{0} l}{L}\)

4. \(\frac{L E_{0} r}{\left(\right. r + r_{1} \left.\right) l}\)

Subtopic: Meter Bridge & Potentiometer |

76%

From NCERT

NEET - 2015

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A potentiometer wire has a length of \(4~\text{m}\) and resistance \(8~\Omega.\) The resistance that must be connected in series with the wire and an energy source of emf \(2~\text{V}\), so as to get a potential gradient of \(1~\text{mV}\) per cm on the wire is:

1. \(32~\Omega\)

2. \(40~\Omega\)

3. \(44~\Omega\)

4. \(48~\Omega\)

Subtopic: Meter Bridge & Potentiometer |

65%

From NCERT

NEET - 2015

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\(\mathrm{A, B}~\text{and}~\mathrm{C}\) are voltmeters of resistance \(R\), \(1.5R\) and \(3R\) respectively as shown in the figure above. When some potential difference is applied between \(\mathrm{X}\) and \(\mathrm{Y}\), the voltmeter readings are \({V}_\mathrm{A}\), \({V}_\mathrm{B}\) and \({V}_\mathrm{C}\) respectively. Then:

1. | \({V}_\mathrm{A} ={V}_\mathrm{B}={V}_\mathrm{C}\) | 2. | \({V}_\mathrm{A} \neq{V}_\text{B}={V}_\mathrm{C}\) |

3. | \({V}_\mathrm{A} ={V}_\mathrm{B}\neq{V}_\mathrm{C}\) | 4. | \({V}_\mathrm{A} \ne{V}_\mathrm{B}\ne{V}_\mathrm{C}\) |

Subtopic: Kirchoff's Voltage Law |

64%

From NCERT

NEET - 2015

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Across a metallic conductor of non-uniform cross-section, a constant potential difference is applied. The quantity which remains constant along the conductor is:

1. | current density | 2. | current |

3. | drift velocity | 4. | electric field |

Subtopic: Current & Current Density |

59%

From NCERT

NEET - 2015

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Two cities are \(150~\text{km}\) apart. Electric power is sent from one city to another city through copper wires. The fall of potential per km is \(8\) volts and the average resistance per km is \(0.5~\text{ohm}\). The power loss in the wire is:

1. \(19.2~\text{W}\)

2. \(19.2~\text{kW}\)

3. \(19.2~\text{J}\)

4. \(12.2~\text{kW}\)

Subtopic: Heating Effects of Current |

82%

From NCERT

AIPMT - 2014

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The figure given below shows a circuit when resistances in the two arms of the meter bridge are \(5~\Omega\) and \(R\), respectively. When the resistance \(R\) is shunted with equal resistance, the new balance point is at \(1.6l_1\). The resistance \(R\) is:

1. \(10~\Omega\)

2. \(15~\Omega\)

3. \(20~\Omega\)

4. \(25~\Omega\)

Subtopic: Meter Bridge & Potentiometer |

73%

From NCERT

AIPMT - 2014

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A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery, used across the potentiometer wire, has an emf of \(2.0~\text{V}\) and negligible internal resistance. The potentiometer wire itself is \(4~\text{m}\) long. When the resistance, \(R\), connected across the given cell, has values of (i) infinity (ii) \(9.5\), the 'balancing lengths, on the potentiometer wire, are found to be \(3~\text{m}\) and \(2.85~\text{m}\), respectively. The value of the internal resistance of the cell is (in ohm):

1. \(0.25\)

2. \(0.95\)

3. \(0.5\)

4. \(0.75\)

Subtopic: Meter Bridge & Potentiometer |

65%

From NCERT

AIPMT - 2014

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A wire of resistance \(4~\Omega\) is stretched to twice its original length. The resistance of a stretched wire would be:

1. \(4~\Omega\)

2. \(8~\Omega\)

3. \(16~\Omega\)

4. \(2~\Omega\)

Subtopic: Derivation of Ohm's Law |

82%

From NCERT

AIPMT - 2013

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Internal resistance of a \(2.1~\text{V}\) cell which gives a current of \(0.2~\text{A}\) through a resistance of \(10~\Omega\) is:

1. \(0.5~\Omega\)

2. \(0.8~\Omega\)

3. \(1.0~\Omega\)

4. \(0.2~\Omega\)

1. \(0.5~\Omega\)

2. \(0.8~\Omega\)

3. \(1.0~\Omega\)

4. \(0.2~\Omega\)

Subtopic: EMF & Terminal Voltage |

83%

From NCERT

AIPMT - 2013

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