- 1(current)
Q. No.\(n\) identical cells, each with an EMF \(E\) and internal resistance \(r,\) are connected in series to form a closed circuit. One of the cells, \(A,\) is connected with its polarity reversed. What is the potential difference across each cell (excluding cell \(A\))?
| 1. | \(\dfrac{2E}{n}\) | 2. | \(\dfrac{E}{n}\) |
| 3. | \(\left(\dfrac{n-2}{n}\right)E\) | 4. | \(\left(\dfrac{2n}{n-2}\right)E\) |
Subtopic: Â Grouping of Cells |
Level 4: Below 35%
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\(18\) cells each having the same EMF are connected in series with some cells being wrongly connected. This arrangement of battery is connected in series with an ammeter and two identical cells which are in series. Current of \(3~\text{A}\) is drawn when cells and battery support each other and current of \(2~\text{A}\) is drawn when cells and battery oppose each other. The number of wrongly connected cells is:
| 1. | \(1\) | 2. | \(2\) |
| 3. | \(3\) | 4. | \(4\) |
Subtopic: Â Grouping of Cells |
Level 3: 35%-60%
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Two non-ideal batteries are connected in parallel: Battery of EMF \(E_1,\) resistance \(r_1\) and of EMF \(E_2\), resistance \(r_2.\) The resulting equivalent battery has EMF '\(E,\)' resistance \(r.\) If \(r_1<r_2,\)
1. \(|E-E_1|<|E-E_2|\)
2. \(|E+E_1|<|E+E_2|\)
3. \(|E-E_1|>|E-E_2|\)
4. \(|E+E_1|>|E+E_2|\)
1. \(|E-E_1|<|E-E_2|\)
2. \(|E+E_1|<|E+E_2|\)
3. \(|E-E_1|>|E-E_2|\)
4. \(|E+E_1|>|E+E_2|\)
Subtopic: Â Grouping of Cells |
Level 3: 35%-60%
Hints
Two hundred cells of the same emf \(E\) and same internal resistance \(r\) are connected in series in the same order without external resistance. The potential drop across \(50\) cells is found to be:
1. \(50E\)
2. \(150E\)
3. \(200E\)
4. zero
1. \(50E\)
2. \(150E\)
3. \(200E\)
4. zero
Subtopic: Â Grouping of Cells |
 50%
Level 3: 35%-60%
Please attempt this question first.
Hints
Please attempt this question first.
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