A battery of emf \(10\) V is connected to resistance as shown in the figure below. The potential difference \(V_{A} - V_{B}\)
between the points \(A\) and \(B\) is:

 

1. \(-2\) V

2. \(2\) V

3. \(5\) V

4. \(\frac{20}{11}~\text{V}\)

What is the equivalent resistance of the circuit​​​​​?

1. \(6~\Omega\)
2. \(7~\Omega\)
3. \(8~\Omega\)
4. \(9~\Omega\)

If each resistance in the figure is \(9~\Omega\), then the reading of the ammeter is:

1. \(5~\text{A}\)
2. \(8~\text{A}\)
3. \(2~\text{A}\)
4. \(9~\text{A}\)

Equivalent resistance across terminals \(A\) and \(B\) will be:

The total current supplied to the circuit by the battery is:

1. \(1~\text{A}\)
2. \(2~\text{A}\)
3. \(4~\text{A}\)
4. \(6~\text{A}\)

In circuit shown below, the resistances are given in ohms and the battery is assumed ideal with emf equal to \(3\) volt. The voltage across the resistance \(R_4\) is:

1. \(0.4\) V
2. \(0.6\) V
3. \(1.2\) V
4. \(1.5\) V

A battery of emf \(E\) and internal resistance \(r\) is connected to a variable resistor \(R\) as shown below. Which one of the following is true​​​​​?

The current in the arm \(CD\) of the circuit will be:
             

1. \(i_{1} + i_{2}\)

2. \(i_{2} + i_{3}\)

3. \(i_{1} + i_{3}\)

4. \(i_{1} - i_{2} + i_{3}\)

Consider the circuit shown in the figure below. The current \(I_3\) is equal to:

1. \(5\) A

2. \(3\) A

3. \(-3\) A

4. \(\frac{-5}{6}\) A

In the Wheatstone's bridge (shown in the figure below) \(X=Y\) and \(A>B\). The direction of the current between \(a\) and \(b\) will be: