The figure shows some of the equipotential surfaces. Magnitude and direction of the electric field is given by:

              

1. 200 V/m, making an angle \(120^\circ\)with the x-axis 
2. 100 V/m, pointing towards the negative x-axis
3. 200 V/m, making an angle \(60^\circ\)with the x-axis
4. 100 V/m, making an angle \(30^\circ\)with the x-axis

Subtopic:  Relation between Field & Potential |
 56%
From NCERT
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In the given figure if V=4 volt, each plate of the capacitor has a surface area of 10-m2 and the plates are 0.1×10-m apart, then the number of excess electrons on the negative plate is:

           

1. 5.15×109

2. 2.21×1010

3. 3.33×109

4. 2.21×109

Subtopic:  Capacitance |
 65%
From NCERT
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Two equal charges q of opposite sign separated by a distance 2a constitute an electric dipole of dipole moment p. If P is a point at a distance r from the centre of the dipole and the line joining the centre of the dipole to this point makes an angle θ with the axis of the dipole, then the potential at P is given by: (r >> 2a) (Where p = 2qa

1. \(V={pcos \theta \over 4 \pi \varepsilon_0r^2}\) 2. \(V={pcos \theta \over 4 \pi \varepsilon_0r}\)
3. \(V={psin \theta \over 4 \pi \varepsilon_0r}\) 4. \(V={pcos \theta \over 2 \pi \varepsilon_0r^2}\)
Subtopic:  Electric Potential |
 72%
From NCERT
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Two thin dielectric slabs of dielectric constants K1&K2 (K1<K2) are inserted between plates of a parallel capacitor, as shown in the figure. The variation of electric field E between the plates with distance d as measured from plate P is correctly shown by:  
  312869

1. 2.
3. 4.
Subtopic:  Dielectrics in Capacitors |
 77%
From NCERT
NEET - 2014
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A conducting sphere of radius R is given a charge Q. The electric potential and field at the center of the sphere respectively are:

1.  Zero and \(\mathrm{Q} / 4 \pi \varepsilon_{\mathrm{o}} \mathrm{R}^2\)
2. \(\mathrm{Q} / 4 \pi \varepsilon_{\mathrm{O}} \mathrm{R}\) and zero
3. \(\mathrm{Q} / 4 \pi \varepsilon_{\mathrm{O}} \mathrm{R}\) and \(\mathrm{Q} / 4 \pi \varepsilon_{\mathrm{o}} \mathrm{R}^2\)
4.  Both are zero


 

Subtopic:  Electrostatic Shielding |
 86%
From NCERT
NEET - 2014
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An electric dipole of moment \(p\) is placed in an electric field of intensity \(E\). The dipole acquires a position such that the axis of the dipole makes an angle \(\theta\) with the direction of the field. Assuming that the potential energy of the dipole to be zero when \(\theta = 90^{\circ},\) the torque and the potential energy of the dipole will respectively be:

1. \(p E \sin \theta,-p E \cos \theta\) 2. \(p E \sin \theta,-2 p E \cos \theta\)
3. \(p E \sin \theta, 2 p E \cos \theta\) 4. \(p E \cos \theta,-p E \sin \theta\)
Subtopic:  Energy of Dipole in an External Field |
 82%
From NCERT
NEET - 2012
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The equivalent capacitance of the following arrangement is:
               
1. 18 μF
2. 9 μF
3. 6 μF
4. 12 μF

Subtopic:  Combination of Capacitors |
 79%
From NCERT
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Two capacitors of capacitance \(6~\mu\text{F}\) and \(3~\mu\text{F}\) are connected in series with battery of \(30~\text{V}\). The charge on \(3~\mu\text{F}\) capacitor at a steady state is:
        
1. \( 3 ~\mu\text{C}\)
2. \( 1.5 ~\mu\text{C}\)
3. \( 60~\mu\text{C}\)
4. \( 900~\mu\text{C}\)

Subtopic:  Combination of Capacitors |
 86%
From NCERT
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Two concentric metallic spherical shells A and B of radii a and b respectively (b>a) are arranged such that outer shell is earthed and inner shell is charged to Q. Charge on the outer surface of outer shell will be:

1. -Qab

2. Q1-ab

3. -Q

4. zero

Subtopic:  Electrostatic Shielding |
From NCERT
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The equivalent capacitance across \(A\) and \(B\) in the given figure is:

   Find equivalent capacitance between points A and B. the answer will be C.
1. \( \frac{3}{2}C\)
2. \(C\)
3. \( \frac{2}{3}C\)
4. \( \frac{5}{3}C\)

Subtopic:  Combination of Capacitors |
 79%
From NCERT
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