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A parallel plate air capacitor has capacitance \(C,\) the distance of separation between plates is \(d\) and potential difference \(V\) is applied between the plates. The force of attraction between the plates of the parallel plate air capacitor is:

1. | \(\frac{C^2V^2}{2d}\) | 2. | \(\frac{CV^2}{2d}\) |

3. | \(\frac{CV^2}{d}\) | 4. | \(\frac{C^2V^2}{2d^2}\) |

Subtopic: Capacitance |

69%

From NCERT

NEET - 2015

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A parallel plate air capacitor of capacitance \(C\) is connected to a cell of emf \(V\) and then disconnected from it. A dielectric slab of dielectric constant \(K,\) which can just fill the air gap of the capacitor is now inserted in it. Which of the following is incorrect?

1. | the potential difference between the plates decreases \(K\) times. |

2. | the energy stored in the capacitor decreases \(K\) times. |

3. | the change in energy stored is \(\frac{1}{2}CV^{2}\left ( \frac{1}{K} -1\right )\) |

4. | the charge on the capacitor is not conserved. |

Subtopic: Energy stored in Capacitor |

71%

From NCERT

NEET - 2015

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Two thin dielectric slabs of dielectric constants \(K_1\)_{ }and \(K_2\) \((K_1<K_2)\) are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field \('E'\) between the plates with distance \('d'\) as measured from the plate \(P\) is correctly shown by:

1. | 2. | ||

3. | 4. |

Subtopic: Dielectrics in Capacitors |

77%

From NCERT

AIPMT - 2014

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A conducting sphere of the radius \(R\) is given a charge \(Q.\) The electric potential and the electric field at the centre of the sphere respectively are:

1. | \(\frac{Q}{4 \pi \varepsilon_0 {R}^2}\) | zero and2. | \(\frac{Q}{4 \pi \varepsilon_0 R}\) and zero |

3. | \(\frac{Q}{4 \pi \varepsilon_0 R}\) and \(\frac{Q}{4 \pi \varepsilon_0{R}^2}\) | 4. | both are zero |

Subtopic: Electric Potential |

83%

From NCERT

AIPMT - 2014

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\(A\), \(B\) and \(C\) are three points in a uniform electric field. The electric potential is:

1. | \(B\) | maximum at

2. | \(C\) | maximum at

3. | \(A, B\) and \(C\) | same at all the three points

4. | \(A\) | maximum at

Subtopic: Relation between Field & Potential |

84%

From NCERT

AIPMT - 2013

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An electric dipole of moment \(p\) is placed in an electric field of intensity \(E.\) The dipole acquires a position such that the axis of the dipole makes an angle \(\theta\) with the direction of the field. Assuming that the potential energy of the dipole to be zero when \(\theta = 90^{\circ}\)$$, the torque and the potential energy of the dipole will respectively be:

1. \(pE\text{sin}\theta, ~-pE\text{cos}\theta\)

2. \(pE\text{sin}\theta, ~-2pE\text{cos}\theta\)

3. \(pE\text{sin}\theta, ~2pE\text{cos}\theta\)

4. \(pE\text{cos}\theta, ~-pE\text{sin}\theta\)

Subtopic: Energy of Dipole in an External Field |

81%

From NCERT

AIPMT - 2012

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Four-point charges \(-Q, -q, 2q~\text{and}~2Q\) are placed, one at each corner of the square. The relation between \(Q\) and \(q\) for which the potential at the center of the square is zero is:

1. | \(Q= -q\) | 2. | \(Q= -2q\) |

3. | \(Q= q\) | 4. | \(Q= 2q\) |

Subtopic: Electric Potential |

76%

From NCERT

AIPMT - 2012

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A parallel plate condenser has a uniform electric field \(E\) (V/m) in the space between the plates. If the distance between the plates is \(d\) (m) and the area of each plate is \(A\) (m^{2}), the energy (joule) stored in the condenser is:

1. \( \frac{1}{2}\varepsilon_0{E}^2 \)

2. \( \frac{{E}^2 {Ad}}{\varepsilon_0} \)

3. \( \frac{1}{2}\varepsilon_0 E^2 Ad \)

4. \(\varepsilon_0 EAd \)

Subtopic: Energy stored in Capacitor |

90%

From NCERT

NEET - 2021

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Four electric charges \(+ q,\) \(+ q,\) \(- q\) and \(- q\) are placed at the corners of a square of side \(2L\) (see figure). The electric potential at point \(A\), mid-way between the two charges \(+ q\) and \(+ q\) is:

1. \(\frac{1}{4 \pi\varepsilon_{0}} \frac{2 q}{L} \left(1 + \frac{1}{\sqrt{5}}\right)\)

2. \(\frac{1}{4 \pi\varepsilon_{0}} \frac{2 q}{L} \left(1 - \frac{1}{\sqrt{5}}\right)\)

3. zero

4. \(\frac{1}{4 \pi \varepsilon_{0}} \frac{2 q}{L} \left(1 + \sqrt{5}\right)\)

Subtopic: Electric Potential |

73%

From NCERT

AIPMT - 2011

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A series combination of n_{1} capacitors, each of value C_{1}, is charged by a source of potential difference 4V. When another parallel combination of n_{2} capacitors, each of value C_{2}, is charged by a source of potential difference V, it has the same (total) energy stored in it, as the first combination has. The value of C_{2}, in terms of C_{1}, is then:

1. $\frac{2{C}_{1}}{{n}_{1}{n}_{2}}$

2. $16\frac{{n}_{2}}{{n}_{1}}{C}_{1}$

3. $2\frac{{n}_{2}}{{n}_{1}}{C}_{1}$

4. $\frac{16{C}_{1}}{{n}_{1}{n}_{2}}$

Subtopic: Energy stored in Capacitor |

73%

From NCERT

AIPMT - 2010

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