The equivalent capacitance of the combination shown in the figure is: 

   

1. C/2

2. 3C/2 

3. 3C 

4. 2C

Subtopic:  Combination of Capacitors |
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A parallel plate capacitor has a uniform electric field \(\vec{E}\) in the space between the plates. If the distance between the plates is \(d\) and the area of each plate is \(A\) the energy stored in the capacitor is: 
\(\left ( \epsilon_{0} = \text{permittivity of free space} \right )\)

1. 12ε0E2Ad

2. E2Adε0

3. 12ε0E2

4. ε0EAd

Subtopic:  Energy stored in Capacitor |
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Two charged spherical conductors of radii R1 and R2 are connected by a wire. The ratio of surface charge densities of spheres \(\left ( \frac{\sigma _{1}}{\sigma _{2}}\right )\) is:
1. R1R2

2. R12R22

3. R1R2

4. R2R1

Subtopic:  Electric Potential |
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Twenty seven drops of same size are charged at 220 V each. They combine to form a bigger drop. Calculate the potential of the bigger drop.

1. 1520 V

2. 1980 V

3. 660 V

4. 1320 V

Subtopic:  Electric Potential |
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In a certain region of space with volume 0.2 m3, the electric potential is found to be 5 V throughout. The magnitude of electric field in this region is:

1. 0.5 N/C

2. 1 N/C

3. 5 N/C

4. zero

Subtopic:  Relation between Field & Potential |
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A short electric dipole has a dipole moment of 16×10-9 C-m. The electric potential due to the dipole at a point at a distance of 0.6 m from the centre of the dipole situated on a line making an angle of 60° with the dipole axis is:

(14πε0=9×109 N-m2/C2)

1. 200 V

2. 400 V

3. zero

4. 50 V

Subtopic:  Energy of Dipole in an External Field |
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The capacitance of a parallel plate capacitor with air as medium is μF. With the introduction of a dielectric medium, the capacitance becomes 30 μF. The permittivity of the medium is: ( εo = 8.85×10-12 C2N-1m-2 )

1. 1.77×10-12 C2N-1m-2

2. 0.44×10-10 C2N-1m-2

3. 5.00 C2N-1m-2

4. 0.44×10-13 C2N-1m-2

Subtopic:  Dielectrics in Capacitors |
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The variation of electrostatic potential with radial distance r from the centre of a positively charged metallic thin shell of radius R is given by the graph:

1. 2.
3. 4.
Subtopic:  Electric Potential |
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A parallel plate capacitor with cross-sectional area A and separation d has air between the plates. An insulating slab of the same area but the thickness of d/2 is inserted between the plates as shown in the figure having a dielectric constant, K=4. The ratio of new capacitance to its original capacitance will be:

1.  2: 1

2.  8: 5

3.  6: 5

4.  4: 1

Subtopic:  Dielectrics in Capacitors |
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Two metal spheres, one of radius \(R\) and the other of radius \(2R\) respectively have the same surface charge density \(\sigma.\) They are brought in contact and separated.  What will be the new surface charge densities on them?
1. \(\sigma_{1}=\frac{5}{6}\sigma ,~\sigma_{2}=\frac{5}{6}\sigma\)
2. \(\sigma_{1}=\frac{5}{2}\sigma ,~\sigma_{2}=\frac{5}{6}\sigma\)
3. \(\sigma_{1}=\frac{5}{2}\sigma ,~\sigma_{2}=\frac{5}{3}\sigma\)
4. \(\sigma_{1}=\frac{5}{3}\sigma ,~\sigma_{2}=\frac{5}{6}\sigma\)
Subtopic:  Electric Potential |
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