The energy stored in the electric field produced by a metal sphere is \(4.5~\text{J}.\) If the sphere contains \(4~\mu\text{C}\) charge, its radius will be:
(Take: \(\frac{1}{4~\pi\epsilon_0}=9\times10^9~\text{N}-\text{m}^2/\text{C}^2)\)
1. \(28~\text{mm}\)
2. \(32~\text{mm}\)
3. \(20~\text{mm}\)
4. \(16~\text{mm}\)
Subtopic:  Energy stored in Capacitor |
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A capacitor with capacitance \(5~\mu\text{F}\) is charged to \(5~\mu \text{C}\). If the plates are pulled apart to reduce the capacitance to \(2~\mu\text{F}\), how much work is done?
1. \( 3.75 \times 10^{-6} ~\text{J} \)
2. \( 6.25 \times 10^{-6} ~\text{J} \)
3. \( 2.55 \times 10^{-6} ~\text{J} \)
4. \( 2.16 \times 10^{-6}~\text{J} \)
 

Subtopic:  Energy stored in Capacitor |
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A \(5~\mathrm{\mu F}\) capacitor is charged fully by a \(220~\text{V}\) supply. It is then disconnected from the supply and is connected in series to another uncharged \(2.5~\mathrm{\mu F}\) capacitor. If the energy change during the charge redistribution is \(\frac{X}{100}~\mathrm{J}\) then value of \(X\) to the nearest integer is:
1. \(10\)
2. \(20\)
3. \(4\)
4. \(1\)

Subtopic:  Energy stored in Capacitor |
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A capacitor \(C\) is fully charged with voltage \(V_0\). After disconnecting the voltage source, it is connected in parallel with another uncharged capacitor of capacitance \(\frac{C}{2}\). The energy loss in the process after the charge is distributed between the two capacitors is: 
1. \( \frac{1}{6} C V_0^2 \)
2. \( \frac{1}{3} C V_0^2 \)
3. \( \frac{1}{4} C V_0^2 \)
4. \( \frac{1}{2} C V_0^2 \)

Subtopic:  Energy stored in Capacitor |
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Two capacitors of capacitances \(C\) and \(2C\) are charged to potential differences \(V\) and \(2V\), respectively. These are then connected in parallel in such a manner that the positive terminal of one is connected to the negative terminal of the other. The final energy of this configuration is:
1. \( \frac{9}{2} C V^2 \)
2. \( \frac{25}{6} C V^2\)
3. zero
4. \( \frac{3}{2} C V^2 \)

Subtopic:  Energy stored in Capacitor |
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A parallel plate capacitor has plate of length ‘\(l\)’, width ‘\(w\)’ and separation of plates is ‘\(d\)’. It is connected to a battery of emf \(V\). A dielectric slab of the same thickness ‘\(d\)’ and of dielectric constant is being inserted between the plates of the capacitor. At what length of the slab inside plates, will be energy stored in the capacitor be two times the initial energy stored?
1. \(l/4\)
2. \(l/2\)
3. \(l/3\)
4. \(2l/3\)

Subtopic:  Energy stored in Capacitor |
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If the charge on a capacitor is increased by \(2~\text C,\) the energy stored in it increases by \(44\text{%}.\) The original charge on the capacitor (in Coulomb) is:
1. \(10\) 
2. \(20\) 
3. \(30\) 
4. \(40\)
Subtopic:  Energy stored in Capacitor |
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A capacitor of capacitance \(50~\text{pF}\) is charged by a \(100~\text{V}\) source. It is then connected to another uncharged identical capacitor. Electrostatic energy loss in the process is:
1. \(25~\text{nJ}\)
2. \(125~\text{nJ}\)
3. \(625~\text{nJ}\)
4. \(1225~\text{nJ}\)
Subtopic:  Energy stored in Capacitor |
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A parallel plate capacitor filled with a medium of dielectric constant \(10\), is connected across a battery and is charged. The dielectric slab is replaced by another slab of dielectric constant \(15\). Then the energy of the capacitor will:
1. increase by \(50\%\)
2. decrease by \(15\%\)
3. increase by \(25\%\)
4. increase by \(33\%\)
Subtopic:  Energy stored in Capacitor |
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A source of potential difference \(V\) is connected to the combination of two identical capacitors as shown in the figure. When key '\(K\)’ is closed, the total energy stored across the combination is \(E_1\). Now key ‘\(K\)’ is opened and dielectric of dielectric constant \(5\) is introduced between the plates of the capacitors. The total energy stored across the combination is now \(E_2\). The ratio \(\frac{E_1}{E_2}\) will be:
        
1. \({1 \over 10}\)
2. \({2 \over 5}\)
3. \({5 \over 13}\)
4. \({5 \over 26}\)
 
Subtopic:  Energy stored in Capacitor |
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