The ratio of the electric flux linked with shell \(A\) and shell \(B\) in the diagram shown below is:

               

1. \(1: 1\)       2. \(1: 2\)      
3. \(1: 4\)       4. \(4: 2\)      
Subtopic:  Gauss's Law |
 89%
From NCERT
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A charge Q is enclosed by a Gaussian spherical surface of radius R. If the radius is doubled, then the outward electric flux will:
1. be reduced to half
2. remain the same
3. be doubled
4. increase four times
Subtopic:  Gauss's Law |
 88%
From NCERT
AIPMT - 2011
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What is the flux through a cube of side \(a,\) if a point charge of \(q\) is placed at one of its corners?
1. \(\frac{2q}{\varepsilon_0}\)
2. \(\frac{q}{8\varepsilon_0}\)
3. \(\frac{q}{\varepsilon_0}\)
4. \(\frac{q}{2\varepsilon_0}\)

Subtopic:  Gauss's Law |
 88%
From NCERT
AIPMT - 2012
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A hollow metal sphere of radius \(R\) is uniformly charged. The electric field due to the sphere at a distance \(r\) from the centre:

1. decreases as \(r\) increases for \(r<R\) and for \(r>R\).
2. increases as \(r\) increases for \(r<R\) and for \(r>R\).
3. is zero as \(r\) increases for \(r<R\), decreases as \(r\) increases for \(r>R\).
4. is zero as \(r\) increases for \(r<R\), increases as \(r\) increases for \(r>R\).
Subtopic:  Gauss's Law |
 81%
From NCERT
NEET - 2019
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Which of the following graphs shows the variation of electric field \(E\) due to a hollow spherical conductor of radius \(R\) as a function of distance from the centre of the sphere?

1. 2.
3. 4.
Subtopic:  Gauss's Law |
 85%
From NCERT
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A square surface of side \(L\) (m) is in the plane of the paper. A uniform electric field \(\vec{E}\) (V/m), also in the plane of the paper, is limited only to the lower half of the square surface, (see figure). The electric flux in SI units associated with the surface is:     
  

1. \(EL^2/ ( 2ε_0 )\) 2.  \(EL^2 / 2\)
3. zero 4. \(EL^2\)
Subtopic:  Gauss's Law |
 81%
From NCERT
AIPMT - 2006
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A hollow cylinder has a charge q coulomb within it (at the geometrical centre). If ϕ is the electric flux in units of Volt-meter associated with the curved surface B, the flux linked with the plane surface A in units of volt-meter will be: 
    

1. 12qε0-Φ


2. q2ε0


3. Φ3


4. qε0-Φ

Subtopic:  Gauss's Law |
 74%
From NCERT
AIPMT - 2007
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A point charge q is placed at the center of the open face of a hemispherical surface as shown in the figure. The flux linked with the surface is:

       

1.  zero

2.  q2ε0

3.  qε0

4.  qπr2

Subtopic:  Gauss's Law |
 72%
From NCERT
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Refer to the arrangement of charges in the figure and a Gaussian surface of radius R with Q at the centre. Then:

a. total flux through the surface of the sphere is -Qε0.
b. field on the surface of the sphere is -Q4πε0R2.
c. flux through the surface of the sphere due to 5Q is zero.
d. field on the surface of the sphere due to -2Q is the same everywhere.

Choose the correct statement(s): 
1.  a and d
2.  a and c
3.  b and d
4.  c and d

Subtopic:  Gauss's Law |
 71%
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If there were only one type of charge in the universe, then,

1. sE.dS0 on any surface.
2. sE.dS=0 if the charge is outside the surface.
3. sE.dS could not be defined.
4. sE.dS=qε0 if charges of magnitude q were inside the surface.
Choose the correct statement(s):
1. a and d
2. a and c
3. b and d
4. c and d
Subtopic:  Gauss's Law |
 72%
From NCERT
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