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The acceleration of an electron due to the mutual attraction between the electron and a proton when they are \(1.6~\mathring{A}\) apart is:

( **\(\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9~ \text{Nm}^2 \text{C}^{-2}\)** )

1. | \( 10^{24} ~\text{m/s}^2\) | 2 | \( 10^{23} ~\text{m/s}^2\) |

3. | \( 10^{22}~\text{m/s}^2\) | 4. | \( 10^{25} ~\text{m/s}^2\) |

Subtopic: Coulomb's Law |

75%

From NCERT

NEET - 2020

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The figure shows electric field lines in which an electric dipole **p** is placed as shown. Which of the following statements is correct?

1. | The dipole will not experience any force. |

2. | The dipole will experience a force towards the right. |

3. | The dipole will experience a force towards the left. |

4. | The dipole will experience a force upwards. |

Subtopic: Electric Dipole |

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The electric field at a point on the equatorial plane at a distance \(r\) from the centre of a dipole having dipole moment $\stackrel{}{}$\(\overrightarrow{P}\) is given by:

(\(r\gg\) separation of two charges forming the dipole, \(\epsilon_{0} =\) permittivity of free space)

1. \(\overrightarrow{E}=\frac{\overrightarrow{P}}{4\pi \epsilon _{0}r^{3}}\)

2. \(\overrightarrow{E}=\frac{2\overrightarrow{P}}{\pi \epsilon _{0}r^{3}}\)

3. \(\overrightarrow{E}=-\frac{\overrightarrow{P}}{4\pi \epsilon _{0}r^{2}}\)

4. \(\overrightarrow{E}=-\frac{\overrightarrow{P}}{4\pi \epsilon _{0}r^{3}}\)

Subtopic: Electric Dipole |

62%

From NCERT

NEET - 2020

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A charge \(q\) is placed in a uniform electric field \(E.\) If it is released, then the kinetic energy of the charge after travelling distance \(y\) will be:

1. \(qEy\)

2. \(2qEy\)

3. $\frac{qEy}{2}$

4. $\sqrt{qEy}$

Subtopic: Electric Field |

75%

From NCERT

AIPMT - 1998

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The electric field at the equator of a dipole is \(E.\) If the strength of the dipole and distance are now doubled, then the electric field will be:

1. | \(E/2\) | 2. | \(E/8\) |

3. | \(E/4\) | 4. | \(E\) |

Subtopic: Electric Dipole |

66%

From NCERT

AIPMT - 1998

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In Millikan oil drop experiment, a charged drop falls with a terminal velocity v. If an electric field E is applied vertically upwards it moves with terminal velocity 2v in upward direction. If electric field reduces to E/2 then its terminal velocity will be:

1. v/2

2. v

3. 3v/2

4. 2v

Subtopic: Electric Field |

From NCERT

AIPMT - 1999

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Refer to the arrangement of charges in the figure and a Gaussian surface of radius R with Q at the centre. Then:

a. | total flux through the surface of the sphere is $\frac{-\mathrm{Q}}{{\epsilon}_{0}}$. |

b. | field on the surface of the sphere is $\frac{-Q}{4\pi {\epsilon}_{0}{R}^{2}}$. |

c. | flux through the surface of the sphere due to 5Q is zero. |

d. | field on the surface of the sphere due to -2Q is the same everywhere. |

Choose the correct statement(s):

1. a and d

2. a and c

3. b and d

4. c and d

Subtopic: Gauss's Law |

71%

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If there were only one type of charge in the universe, then,

1. | ${\oint}_{s}E.dS\ne 0$ on any surface. |

2. | ${\oint}_{s}E.dS=0$ if the charge is outside the surface. |

3. | ${\oint}_{s}E.dS$ could not be defined. |

4. | ${\oint}_{s}E.\mathrm{dS}=\frac{q}{{\epsilon}_{0}}$ if charges of magnitude q were inside the surface. |

1. a and d

2. a and c

3. b and d

4. c and d

Subtopic: Gauss's Law |

72%

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Two point dipoles of dipole moment ${\overrightarrow{\mathrm{p}}}_{1}$ and ${\overrightarrow{\mathrm{p}}}_{2}$ are at a distance x from each other and ${\overrightarrow{\mathrm{p}}}_{1}\left|\right|{\overrightarrow{\mathrm{p}}}_{2}$. The force between the dipole is:

1. $\frac{1}{4{\mathrm{\pi \epsilon}}_{0}}\frac{4{p}_{1}{p}_{2}}{{x}^{4}}$

2. $\frac{1}{4{\mathrm{\pi \epsilon}}_{0}}\frac{3{p}_{1}{p}_{2}}{{x}^{3}}$

3. $\frac{1}{4{\mathrm{\pi \epsilon}}_{0}}\frac{6{p}_{1}{p}_{2}}{{x}^{4}}$

4. $\frac{1}{4{\mathrm{\pi \epsilon}}_{0}}\frac{8{p}_{1}{p}_{2}}{{x}^{4}}$

Subtopic: Electric Dipole |

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A hollow metal sphere of radius \(R\) is uniformly charged. The electric field due to the sphere at a distance \(r\) from the centre:

1. | decreases as \(r\) increases for \(r<R\) and for \(r>R\). |

2. | increases as \(r\) increases for \(r<R\) and for \(r>R\). |

3. | is zero as \(r\) increases for \(r<R\), decreases as \(r\) increases for \(r>R\). |

4. | is zero as \(r\) increases for \(r<R\), increases as \(r\) increases for \(r>R\). |

Subtopic: Gauss's Law |

81%

From NCERT

NEET - 2019

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