The acceleration of an electron due to the mutual attraction between the electron and a proton when they are \(1.6~\mathring{A}\) apart is:
\(\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9~ \text{Nm}^2 \text{C}^{-2}\) )

1. \( 10^{24} ~\text{m/s}^2\) 2 \( 10^{23} ~\text{m/s}^2\)
3. \( 10^{22}~\text{m/s}^2\) 4. \( 10^{25} ~\text{m/s}^2\)

Subtopic:  Coulomb's Law |
 75%
From NCERT
NEET - 2020
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The figure shows electric field lines in which an electric dipole p is placed as shown. Which of the following statements is correct?
                      

1. The dipole will not experience any force.
2. The dipole will experience a force towards the right.
3. The dipole will experience a force towards the left.
4. The dipole will experience a force upwards.

Subtopic:  Electric Dipole |
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The electric field at a point on the equatorial plane at a distance \(r\) from the centre of a dipole having dipole moment \(\overrightarrow{P}\) is given by:
(\(r\gg\) separation of two charges forming the dipole, \(\epsilon_{0} =\) permittivity of free space) 
1. \(\overrightarrow{E}=\frac{\overrightarrow{P}}{4\pi \epsilon _{0}r^{3}}\) 

2. \(\overrightarrow{E}=\frac{2\overrightarrow{P}}{\pi \epsilon _{0}r^{3}}\)

3. \(\overrightarrow{E}=-\frac{\overrightarrow{P}}{4\pi \epsilon _{0}r^{2}}\)

4. \(\overrightarrow{E}=-\frac{\overrightarrow{P}}{4\pi \epsilon _{0}r^{3}}\)

Subtopic:  Electric Dipole |
 62%
From NCERT
NEET - 2020
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A charge \(q\) is placed in a uniform electric field \(E.\) If it is released, then the kinetic energy of the charge after travelling distance \(y\) will be:
1. \(qEy\)
2. \(2qEy\)
3. qEy2
4. qEy

Subtopic:  Electric Field |
 75%
From NCERT
AIPMT - 1998
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The electric field at the equator of a dipole is \(E.\) If the strength of the dipole and distance are now doubled, then the electric field will be:

1. \(E/2\) 2. \(E/8\)
3. \(E/4\) 4. \(E\)
Subtopic:  Electric Dipole |
 66%
From NCERT
AIPMT - 1998
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In Millikan oil drop experiment, a charged drop falls with a terminal velocity v. If an electric field E is applied vertically upwards it moves with terminal velocity 2v in upward direction. If electric field reduces to E/2 then its terminal velocity will be:
1. v/2
2. v
3. 3v/2
4. 2v

Subtopic:  Electric Field |
From NCERT
AIPMT - 1999
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Refer to the arrangement of charges in the figure and a Gaussian surface of radius R with Q at the centre. Then:

a. total flux through the surface of the sphere is -Qε0.
b. field on the surface of the sphere is -Q4πε0R2.
c. flux through the surface of the sphere due to 5Q is zero.
d. field on the surface of the sphere due to -2Q is the same everywhere.

Choose the correct statement(s): 
1.  a and d
2.  a and c
3.  b and d
4.  c and d

Subtopic:  Gauss's Law |
 71%
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If there were only one type of charge in the universe, then,

1. sE.dS0 on any surface.
2. sE.dS=0 if the charge is outside the surface.
3. sE.dS could not be defined.
4. sE.dS=qε0 if charges of magnitude q were inside the surface.
Choose the correct statement(s):
1. a and d
2. a and c
3. b and d
4. c and d
Subtopic:  Gauss's Law |
 72%
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Two point dipoles of dipole moment p1 and p2 are at a distance x from each other and p1||p2. The force between the dipole is:

1. 14πε04p1p2x4

2. 14πε03p1p2x3

3. 14πε06p1p2x4

4. 14πε08p1p2x4

Subtopic:  Electric Dipole |
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A hollow metal sphere of radius \(R\) is uniformly charged. The electric field due to the sphere at a distance \(r\) from the centre:

1. decreases as \(r\) increases for \(r<R\) and for \(r>R\).
2. increases as \(r\) increases for \(r<R\) and for \(r>R\).
3. is zero as \(r\) increases for \(r<R\), decreases as \(r\) increases for \(r>R\).
4. is zero as \(r\) increases for \(r<R\), increases as \(r\) increases for \(r>R\).
Subtopic:  Gauss's Law |
 81%
From NCERT
NEET - 2019
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