Assertion (A): | While applying Gauss’s law, the axis of the Gaussian cylinder should coincide with the line. |
Reason (R): | In the case of a Gaussian cylinder, the Gaussian surface should be drawn in such a manner that it encloses the charge whose electric field is to be found. |
In the light of the above statements choose the correct answer from the options given below:
1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
3. | (A) is true but (R) is false. |
4. | (A) is false but (R) is true. |
Given below are two statements:
Assertion (A): | The number of field lines drawn from a charge is proportional to the magnitude of the charge. |
Reason (R): | The electric field at any point is proportional to the magnitude of the source charge. |
1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
3. | (A) is True but (R) is False. |
4. | Both (A) and (R) are False. |
Assertion (A): | If two charged bodies placed near each other attract each other then they must be oppositely charged. |
Reason (R): | Unlike charges repel each other and like charges attract each other. |
1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
3. | (A) is true but (R) is false. |
4. | Both (A) and (R) are false. |
Assertion (A): | If a proton and an electron are placed in the same uniform electric field then they experience different accelerations. |
Reason (R): | Electric force on a test charge is independent of its mass. |
1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
3. | (A) is true but (R) is false. |
4. | (A) is false but (R) is true. |
The figure shows some of the electric field lines corresponding to an electric field. The figure suggests:
1. EA > EB > EC
2. EA = EB = EC
3. EA = EC > EB
4. EA = EC < EB
If \(\int_S E.ds = 0\) over a surface, then:
(a) | the electric field inside the surface and on it is zero. |
(b) | the electric field inside the surface is necessarily uniform. |
(c) | the number of flux lines entering the surface must be equal to the number of flux lines leaving it. |
(d) | all charges must necessarily be outside the surface. |
Choose the correct statement(s):
1. (a), (c)
2. (b), (c)
3. (c), (d)
4. (a), (d)
(a) | always continuous. |
(b) | continuous if there is no charge at that point. |
(c) | discontinuous only if there is a negative charge at that point. |
(d) | discontinuous if there is a charge at that point. |
Choose the correct option:
1. | (a), (b) | 2. | (b), (d) |
3. | (c), (d) | 4. | (a), (d) |
The electric flux through the surface,
(i) | (ii) |
(iii) | (iv) |
1. in figure (IV) is the largest
2. in figure (III) is the least
3. in figure (II) is same as in figure (III) but is smaller than figure (IV)
4. is the same for all figures
1. | \(\oint_{s} \vec{E} \cdot d \vec{s} \neq 0\) on any surface. |
2. | \(\oint_{s} \vec{E} \cdot d \vec{s}=0\) if the charge is outside the surface. |
3. | \(\oint_{s} \vec{E} \cdot d \vec{s}=\frac{q}{\varepsilon_{0}}\) if charges of magnitude \(q\) were inside the surface. |
4. | Both (2) and (3) are correct. |