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Q. No.The figure shows some of the electric field lines corresponding to an electric field. The figure suggests:
1. EA > EB > EC
2. EA = EB = EC
3. EA = EC > EB
4. EA = EC < EB
Subtopic: Electric Field |
84%
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If \(\int_S E.ds = 0\) over a surface, then:
| a. | the electric field inside the surface and on it is zero. |
| b. | the electric field inside the surface is necessarily uniform. |
| c. | the number of flux lines entering the surface must be equal to the number of flux lines leaving it. |
| d. | all charges must necessarily be outside the surface. |
1. (a, c)
2. (b, c)
3. (c, d)
4. (a, d)
Subtopic: Gauss's Law |
53%
From NCERT
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Links
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The electric field at a point is:
| a. | always continuous |
| b. | continuous if there is no charge at that point |
| c. | discontinuous only if there is a negative charge at that point |
| d. | discontinuous if there is a charge at that point |
1. (a, b)
2. (b, d)
3. (c, d)
4. (a, d)
Subtopic: Electric Field |
61%
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The electric flux through the surface,
 |
 |
| (i) | (ii) |
 |
 |
| (iii) | (iv) |
1. in figure (IV) is the largest
2. in figure (III) is the least
3. in figure (II) is same as in figure (III) but is smaller than figure (IV)
4. is the same for all figures
Subtopic: Gauss's Law |
93%
From NCERT
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If there were only one type of charge in the universe, then:
| 1. | \(\oint_{s} \vec{E} \cdot d \vec{s} \neq 0\) on any surface. |
| 2. | \(\oint_{s} \vec{E} \cdot d \vec{s}=0\)if the charge is outside the surface. |
| 3. | \(\oint_{s} \vec{E} \cdot d \vec{s}=\frac{q}{\varepsilon_{0}}\) if charges of magnitude q were inside the surface. |
| 4. | both (2) and (3) are correct. |
Subtopic: Gauss's Law |
87%
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Which of the following field configurations is/are possible?
Note: A, B, C are conductors. Other charges may be present in the vicinity.
1. I, III
2. II
3. I, II, III
4. none of I, II, III
Note: A, B, C are conductors. Other charges may be present in the vicinity.
1. I, III
2. II
3. I, II, III
4. none of I, II, III
Subtopic: Electric Field |
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Given below are two statements:
| Assertion (A): | Point charges \(q_{1}\) and \(q_{2}\) produce electric field of magnitude \(E_{1}\) and \(E_{2}\) at a point and potential \(V_{1}\) and \(V_{2}\) at the same point. The electric field due to both the charges at that point must be \(E_{1}+E_{2}.\) |
| Reason (R): | The electric potential at that point due to both the charges must be \(V_{1}+V_{2}.\) |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | (A) is false but (R) is true. |
Subtopic: Electric Field |
60%
From NCERT
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Given below are two statements:
| Assertion (A): | Mass of a body decreases slightly when it is negatively charged. |
| Reason (R): | Charging is due to the transfer of electrons. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
Subtopic: Electric Charge |
80%
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Given below are two statements:
| Assertion (A): | If electrons in an atom were stationary, then they would fall into the nucleus. |
| Reason (R): | Electrostatic force of attraction acts between negatively charged electrons and positive nucleus. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | (A) is false but (R) is true. |
Subtopic: Coulomb's Law |
66%
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Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R):
In light of the above statements choose the correct answer from the options given below:
| Assertion (A): | If the electric field due to a dipole on its axis line at a distance r is E, then the electric field due to a dipole at the same distance at the equatorial line will be E/2. |
| Reason (R): | Electric field due to dipole varies inversely as the square of the distance. |
In light of the above statements choose the correct answer from the options given below:
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | Both (A) and (R) are false. |
Subtopic: Electric Dipole |
68%
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