If \(\oint_s \vec{E} \cdot \overrightarrow{d S}=0\) over a surface, then:

1. | the electric field inside the surface is necessarily uniform. |

2. | the number of flux lines entering the surface must be equal to the number of flux lines leaving it. |

3. | the magnitude of electric field on the surface is constant. |

4. | all the charges must necessarily be inside the surface. |

Subtopic: Gauss's Law |

78%

From NCERT

NEET - 2023

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According to Gauss law of electrostatics, electric flux through a closed surface depends on:

1. | the area of the surface |

2. | the quantity of charges enclosed by the surface |

3. | the shape of the surface |

4. | the volume enclosed by the surface |

Subtopic: Gauss's Law |

81%

From NCERT

NEET - 2023

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A charge \(Q~\mu\text{C}\) is placed at the centre of a cube. The flux coming out from any one of its faces will be: (in SI unit)

1. | \(\frac{Q}{\varepsilon_0}\times10^{-6}\) | 2. | \(\frac{2Q}{3\varepsilon_0}\times10^{-3}\) |

3. | \(\frac{Q}{6\varepsilon_0}\times10^{-3}\) | 4. | \(\frac{Q}{6\varepsilon_0}\times10^{-6} \) |

Subtopic: Gauss's Law |

74%

From NCERT

NEET - 2023

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Two parallel infinite line charges with linear charge densities \(+\lambda\) C/m and \(+\lambda\) C/m are placed at a distance \({R}.\) The electric field mid-way between the two line charges is:

1. \(\frac{\lambda}{2 \pi \varepsilon_0 {R}} \) N/C

2. zero

3. \(\frac{2\lambda}{ \pi \varepsilon_0 {R}} \) N/C

4. \(\frac{\lambda}{ \pi \varepsilon_0 {R}}\) N/C

Subtopic: Gauss's Law |

64%

From NCERT

NEET - 2019

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A sphere encloses an electric dipole with charges \(\pm3\times10^{-6}\) C. What is the total electric flux through the sphere?

1. \(-3\times10^{-6}\) N-m^{2}/C

2. zero

3. \(3\times10^{-6}\) N-m^{2}/C

4. \(6\times10^{-6}\) N-m^{2}/C

Subtopic: Gauss's Law |

89%

From NCERT

NEET - 2019

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The electric field in a certain region is acting radially outward and is given by \(E=Ar.\) A charge contained in a sphere of radius \(a\) centered at the origin of the field will be given by:

1. \(4 \pi \varepsilon_{{o}} {A}{a}^2\)

2. \(\varepsilon_{{o}} {A} {a}^2\)

3. \(4 \pi \varepsilon_{{o}} {A} {a}^3\)

4. \(\varepsilon_{{o}} {A}{a}^3\)

Subtopic: Gauss's Law |

67%

From NCERT

NEET - 2015

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What is the flux through a cube of side \(a,\) if a point charge of \(q\) is placed at one of its corners?

1. \(\frac{2q}{\varepsilon_0}\)

2. \(\frac{q}{8\varepsilon_0}\)

3. \(\frac{q}{\varepsilon_0}\)

4. \(\frac{q}{2\varepsilon_0}\)

Subtopic: Gauss's Law |

87%

From NCERT

AIPMT - 2012

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A charge Q is enclosed by a Gaussian spherical surface of radius R. If the radius is doubled, then the outward electric flux will:

1. be reduced to half

2. remain the same

3. be doubled

4. increase four times

1. be reduced to half

2. remain the same

3. be doubled

4. increase four times

Subtopic: Gauss's Law |

88%

From NCERT

AIPMT - 2011

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The electric field at a distance \(\frac{3R}{2}\) from the centre of a charged conducting spherical shell of radius \(R\) is \(E\). The electric field at a distance \(\frac{R}{2}\) from the centre of the sphere is:

1. \(E\)

2. \(\frac{E}{2}\)

3. \(\frac{E}{3}\)

4. zero

Subtopic: Gauss's Law |

84%

From NCERT

AIPMT - 2010

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A hollow cylinder has a charge *q* coulomb within it (at the geometrical centre). If ϕ is the electric flux in units of Volt-meter associated with the curved surface B, the flux linked with the plane surface A in units of volt-meter will be:

1. $\frac{1}{2}\left(\frac{q}{{\epsilon}_{0}}-\Phi \right)$

2. $\frac{q}{2{\epsilon}_{0}}$

3. $\frac{\Phi}{3}$

4. $\frac{q}{{\epsilon}_{0}}-\Phi $

Subtopic: Gauss's Law |

74%

From NCERT

AIPMT - 2007

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