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# A dipole of moment $\stackrel{\to }{p}$ is placed in uniform electric field $\stackrel{\to }{E}$. The torque acting on it is given by: 1. $$\vec{\tau }=\vec{p}.\vec{E}$$ 2. $$\vec{\tau }=\vec{p} \times\vec{E}$$ 3. $$\vec{\tau }=\vec{p}+\vec{E}$$ 4. $$\vec{\tau }=\vec{p}-\vec{E}$$

Subtopic:  Electric Dipole |
90%
From NCERT
AIPMT - 2001
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A charge q is located at the centre of a cube. The electric flux through any face is:

1. $\frac{2\mathrm{\pi q}}{6\left(4{\mathrm{\pi \epsilon }}_{0}\right)}$

2. $\frac{4\mathrm{\pi q}}{6\left(4{\mathrm{\pi \epsilon }}_{0}\right)}$

3. $\frac{\mathrm{\pi q}}{6\left(4{\mathrm{\pi \epsilon }}_{0}\right)}$

4. $\frac{\mathrm{q}}{6\left(4{\mathrm{\pi \epsilon }}_{0}\right)}$

Subtopic:  Gauss's Law |
67%
From NCERT
AIPMT - 2003
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If a charge Q µC is placed at the centre of the cube, the flux (In SI unit) coming out from any surface will be:

1.  $\frac{Q}{6{\epsilon }_{0}}$ $×$ ${10}^{-6}$

2.  $\frac{Q}{6{\epsilon }_{0}}$ $×$ ${10}^{-3}$

3.  $\frac{Q}{2{\epsilon }_{0}}$ 

4. $\frac{Q}{8{\epsilon }_{0}}$ 

Subtopic:  Gauss's Law |
86%
From NCERT
AIPMT - 2001
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In Millikan oil drop experiment, a charged drop falls with a terminal velocity $$v$$. If an electric field $$E$$ is applied vertically upwards it moves with terminal velocity $$2v$$ in upward direction. If electric field reduces to $$\frac{E}{2}$$ then its terminal velocity will be:
1. $$\frac{v}{2}$$
2. $$v$$
3. $$\frac{3v}{2}$$
4. $$2v$$

Subtopic:  Electric Field |
From NCERT
AIPMT - 1999
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The unit of permittivity of free space $$\varepsilon_0$$ is:
 1 Newton metre2 / Coulomb2 2 Coulomb2 /Newton metre2 3 Coulomb2/ (Newton metre)2 4 Coulomb/Newton metre

Subtopic:  Coulomb's Law |
72%
From NCERT
AIPMT - 2004
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Polar molecules are the molecules:

 1 that acquires a dipole moment only when the magnetic field is absent. 2 has a permanent electric dipole moment. 3 has zero dipole moment. 4 that acquire a dipole moment only in the presence of an electric field due to displacement of charges.
Subtopic:  Electric Dipole |
64%
From NCERT
NEET - 2021
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A dipole is placed in an electric field as shown. In which direction will it move?

 1 towards the left as its potential energy will decrease. 2 towards the right as its potential energy will increase. 3 towards the left as its potential energy will increase. 4 towards the right as its potential energy will decrease.
Subtopic:  Electric Dipole |
From NCERT
NEET - 2021
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A point $$Q$$ lies on the perpendicular bisector of an electric dipole of dipole moment $$p.$$ If the distance of $$Q$$ from the dipole is $$r$$ (much larger than the size of the dipole), then the electric field at $$Q$$ is proportional to:
1. $$p^{2}$$ and $$r^{-3}$$
2. $$p$$ and $$r^{-2}$$
3. $$p^{-1}$$ and $$r^{-2}$$
4. $$p$$ and $$r^{-3}$$

Subtopic:  Electric Dipole |
86%
From NCERT
AIPMT - 1998
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The electric field at the equator of a dipole is $$E.$$ If the strength of the dipole and distance are now doubled, then the electric field will be:

 1 $$E/2$$ 2 $$E/8$$ 3 $$E/4$$ 4 $$E$$
Subtopic:  Electric Dipole |
66%
From NCERT
AIPMT - 1998
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A charge $$q$$ is placed in a uniform electric field $$E.$$ If it is released, then the kinetic energy of the charge after travelling distance $$y$$ will be:

 1 $$qEy$$ 2 $$2qEy$$ 3 $\frac{qEy}{2}$ 4 $\sqrt{qEy}$
Subtopic:  Electric Field |
76%
From NCERT
AIPMT - 1998
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