Two charges \(\pm10~\mu\text{C}\) are placed \(5.0\) mm apart. The electric field at a point \(P\) on the axis of the dipole \(15\) cm away from its centre \(O\) on the side of the positive charge, as shown in the figure is:

        
1. \(2.7\times10^5~\text{NC}^{-1}\)
2.
\(4.13\times10^6~\text{NC}^{-1}\)
3. \(3.86\times10^6~\text{NC}^{-1}\)
4. \(1.33\times10^5~\text{NC}^{-1}\)

Subtopic:  Electric Dipole |
 56%
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Two charges \(\pm 10~ \mu \text{C}\) are placed \(5.0\) mm apart. The electric field at a point \(Q\), \(15\) cm away from O on a line passing through \(O\) and normal to the axis of the dipole, as shown in the figure is:

         

1. \(2.8 \times 10^5~\text{NC}^{-1}\)
2. \(3.9\times 10^5 ~\text{NC}^{-1}\)
3. \(1.33\times 10^5 ~\text{NC}^{-1}\)
4. \(4.1\times 10^6 ~\text{NC}^{-1}\)

Subtopic:  Electric Dipole |
 68%
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The electric field components in the shown figure are Ex=αx1/2Ey = Ez = 0, in which  α=800 N/C m1/2. The net flux through the cube is: (Assume that a = 0.1 m)

1. 1.05  Nm2C-1
2.  2.03  Nm2C-1
3. 3.05  Nm2C-1
4. 4.03  Nm2C-1 

Subtopic:  Gauss's Law |
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The electric field components in the shown figure are Ex=ax1/2Ey = Ez = 0, in which  α=800 N/C m1/2. Find the charge within the cube if net flux through the cube is 1.05 N m2 C-1: (Assume that a = 0.1 m). 

1. Zero
2. 2.7×10-12 C
3. 7.9×10-12 C
4. 9.2×10-12 C

Subtopic:  Gauss's Law |
 54%
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An electric field is uniform, and in the positive \(x\)-direction for positive \(x\), and uniform with the same magnitude but in the negative \(x\)-direction for negative \(x\). It is given that \(\vec{E}=200\hat{i}\) N/C for \(x>0\) and \(\vec{E}=-200\hat{i}\)  N/C for \(x<0\). A right circular cylinder of length \(20~\text{cm}\) and radius \(5~\text{cm}\) has its centre at the origin and its axis along the \(x\text{-}\)axis so that one face is at \(x= + 10~\text{cm}\) and the other is at \(x= -10~\text{cm}\) (as shown in the figure). What is the net outward flux through the cylinder?
        
1. \(0\) 
2. \(1.57~\text{Nm}^2\text{C}^{-1}\)
3. \(3.14~\text{Nm}^2\text{C}^{-1}\)
4. \(2.47~\text{Nm}^2\text{C}^{-1}\)

Subtopic:  Gauss's Law |
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An electric field is uniform, and in the positive x-direction for positive x, and uniform with the same magnitude but in the negative x-direction for negative x. It is given that E =200 i^ N/C for x > 0 and E = –200 i^ N/C for x < 0. A right circular cylinder of length 20 cm and radius 5 cm has its centre at the origin and its axis along the x-axis so that one face is at x = +10 cm and the other is along the x-axis so that one face is at x = +10 cm and the other is at x = –10 cm (as shown in the figure). What is the net charge inside the cylinder?

1. 2.78×10-11 C
2 3.10×10-12 C
3. 1.37×10-10 C
4. 2.62×10-12 C

Subtopic:  Gauss's Law |
 59%
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An early model for an atom considered it to have a positively charged point nucleus of charge Ze, surrounded by a uniform density of negative charge up to a radius R. The atom as a whole is neutral. For this model, the electric field at a distance r(r<R) from the nucleus is:

1. Ze4πε01r2-rR3
2. Ze4πε01R2
3. Ze4πε01r2
4. Ze4πε0rR3

Subtopic:  Gauss's Law |
 58%
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An early model for an atom considered it to have a positively charged point nucleus of charge Ze, surrounded by a uniform density of negative charge up to a radius R. The atom as a whole is neutral. For this model, the electric field at a distance r (r>R) from the nucleus is:

1. Ze4πε01r2-rR3
2. 0
3. Ze4πε01r2
4. Ze4πε0rR3

Subtopic:  Gauss's Law |
 55%
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The accelerations of electron and proton due to the electrical force of their mutual attraction when they are 1 Å (=10-10 m) apart are respectively: (\(m_p=1.67\times10^{-27}~\text{kg},~m_e=9.11\times10^{-31}~\text{kg}\))

1. \(2.5\times10^{22}\) m/s2\(2.5\times10^{22}\) m/s2 
2. \(2.5\times10^{22}\) m/s2\(1.4\times10^{19}\) m/s2
3. \(1.4\times10^{19}\) m/s2\(2.5\times10^{22}\) m/s2
4. \(1.4\times10^{19}\) m/s2\(1.4\times10^{19}\) m/s2

Subtopic:  Coulomb's Law |
 67%
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Two-point charges q1 and q2, of magnitude +10-8 C  and -10-8 C, respectively, are placed 0.1 m apart. The electric field at point  A (as shown in the figure) is: 

          

1. 3.6×104 NC-1
2. 7.2×104 NC-1
3. 9×103 NC-1
4. 3.2×104 NC-1

Subtopic:  Electric Field |
 54%
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