Suppose the charge of a proton and an electron differ slightly. One of them is $$-e$$, the other is ($$e+\Delta e$$). If the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance $$d$$ (much greater than atomic size) apart is zero, then $$\Delta e$$ is of the order of? (Given mass of hydrogen ${\mathrm{}}_{}$$$m_h = 1.67\times 10^{-27}~\text{kg}$$)
1. $$10^{-23}~\text{C}$$
2. $$10^{-37}~\text{C}$$
3. $$10^{-47}~\text{C}$$
4. $$10^{-20}~\text{C}$$

Subtopic: Â Coulomb's Law |
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From NCERT
NEET - 2017
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Two identical charged spheres suspended from a common point by two massless strings of lengths l are initially at a distance d(d < < l) apart because of their mutual repulsion. The charges begin to leak from both the spheres at a constant rate. As a result, the spheres approach each other with a velocity v. Then, v varies as a function of the distance x between the sphere, as:

(a) $$v \propto x$$

(b) $$v \propto x^{\frac{-1}{2}}$$

(c) $$v \propto x^{-1}$$

(d) $$v \propto x^{\frac{1}{2}}$$${\frac{}{}}^{}$

Subtopic: Â Coulomb's Law |
Â 68%
From NCERT
NEET - 2016
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Two identical charged spheres suspended from a common point by two massless strings of lengths $$l,$$ are initially at a distance $$d$$ $$\left ( d\ll l \right )$$ apart because of their mutual repulsion. The charges begin to leak from both the spheres at a constant rate. As a result, the spheres approach each other with a velocity $$v.$$ Then, $$v$$ varies as a function of the distance $$x$$ between the sphere, as:
1. $$v\propto x$$
2. $$v\propto x^{-1/2}$$
3. $$v\propto x^{-1}$$
4. $$v\propto x^{1/2}$$
Subtopic: Â Coulomb's Law |
Â 78%
From NCERT
NEET - 2016
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