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Q. No.Consider an \(HCl\) molecule, where one of its electrons is located exactly midway between the two nuclei, at a given instant. Ignore all the other electrons and any quantum effects.
Let \(\vec F_H\) be the electrostatic force exerted by the electron on the \(H\)-nucleus and \(\vec F_{Cl}\) be the force exerted by the electron on the \(Cl\) nucleus. Then:
Let \(\vec F_H\) be the electrostatic force exerted by the electron on the \(H\)-nucleus and \(\vec F_{Cl}\) be the force exerted by the electron on the \(Cl\) nucleus. Then:
| 1. | \(|\vec F_{Cl}|=|\vec F_H|\)and \(\vec F_{Cl}\) is opposite to \(\vec F_H\) |
| 2. | \(|\vec F_{Cl}|=|\vec F_H|\)and \(\vec F_{Cl}\) & \(\vec F_H\) are in the same direction |
| 3. | \(|\vec F_{Cl}|>|\vec F_H\) and \(\vec F_{Cl}\) is opposite to \(\vec F_H\) |
| 4. | \(|\vec F_{Cl}|<|\vec F_H|\) and \(\vec F_{Cl}\) is opposite to \(\vec F_H\) |
Subtopic: Â Coulomb's Law |
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