An ideal spring with spring-constant K is hung from the ceiling and a block of mass M is attached to its lower end. The mass is released with the spring initially un-stretched. Then the maximum extension in the spring will be:
1. 4 Mg/K 
2. 2 Mg/K
3. Mg/K 
4. Mg/2K

Subtopic:  Spring mass system |
 56%
From NCERT
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The velocity-time diagram of a harmonic oscillator is shown in the figure given below. The frequency of oscillation will be:
                

1. 25 Hz
2. 50 Hz
3. 12.25 Hz
4. 33.3 Hz

Subtopic:  Simple Harmonic Motion |
 73%
From NCERT
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The variation of the potential energy of the harmonic oscillator is shown in the figure. The spring constant will be:
           

1. 1  × 102 N/m 2. 150 N/m
3. 0.667  × 102 N/m 4. 3  × 102 N/m
Subtopic:  Energy of SHM |
 62%
From NCERT
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A particle moves according to the law, x=r cosπt2. The distance covered by it in the time interval between t =0 to t =3 s will be:

1. r 2. 2r
3. 3r 4. 4r
Subtopic:  Linear SHM |
From NCERT
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A mass of 30 g is attached with two springs having spring constant 100 N/m and 200 N/m and other ends of springs are attached to rigid walls as shown in the given figure. The angular frequency of oscillation will be
                         
       

1.  1002π rad/s

2.  100π rad/s

3.  100 rad/s

4.  200π rad/s

Subtopic:  Combination of Springs |
 67%
From NCERT
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If a particle in SHM has a time period of \(0.1\) s and an amplitude of \(6\) cm, then its maximum velocity will be:
1. \(120 \pi\) cm/s 

2. \(0.6 \pi\) cm/s 

3. \(\pi\) cm/s

4. \(6\) cm/s

Subtopic:  Simple Harmonic Motion |
 90%
From NCERT
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If the potential energy U (in J) of a body executing SHM is given by U = 20 + 10 (sin2100πt), then the minimum potential energy of the body will be:

1. Zero 2. 30 J
3. 20 J 4. 40 J
Subtopic:  Energy of SHM |
 72%
From NCERT
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The kinetic energy (K) of a simple harmonic oscillator varies with displacement (x) as shown. The period of the oscillation will be: (mass of oscillator is 1 kg)

                     

1. π2 sec 2.  12 sec
3.  π sec 4. 1 sec
Subtopic:  Energy of SHM |
 75%
From NCERT
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The equation of an SHM is given as y=3sinωt + 4cosωt where y is in centimeters. The amplitude of the SHM will be?

1. 3 cm 2. 3.5 cm
3. 4 cm 4. 5 cm
Subtopic:  Linear SHM |
 90%
From NCERT
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The time periods for the figures (a) and (b) are T1 and T2 respectively. If all surfaces shown below are smooth, then the ratio T1T2 will be:
   

1.  1: 3

2.  1: 1

3.  2: 1

4.  3: 2

Subtopic:  Spring mass system |
 81%
From NCERT
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