The mean free path \(l\) for a gas molecule depends upon the diameter, \(d\) of the molecule as:
1. \(l\propto \frac{1}{d^2}\)
2. \(l\propto d\)
3. \(l\propto d^2 \)
4. \(l\propto \frac{1}{d}\)

Subtopic:  Mean Free Path |
 84%
From NCERT
NEET - 2020
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The mean free path for a gas, with molecular diameter \(d\) and number density \(n,\) can be expressed as:
1. \( \frac{1}{\sqrt{2} n \pi \mathrm{d}^2} \)
2. \( \frac{1}{\sqrt{2} n^2 \pi \mathrm{d}^2} \)
3. \(\frac{1}{\sqrt{2} n^2 \pi^2 d^2} \)
4. \( \frac{1}{\sqrt{2} n \pi \mathrm{d}}\)

Subtopic:  Mean Free Path |
 81%
From NCERT
NEET - 2020
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If the mean free path of atoms is doubled , then the pressure of the gas will become:

1. P/4                       

2. P/2

3. P/8                       

4. P

Subtopic:  Mean Free Path |
 72%
From NCERT
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If the pressure in a closed vessel is reduced by drawing out some gas, the mean free path of the molecules:

1. decreases
2. increases
3. remains unchanged
4. increases or decreases according to the nature of the gas

Subtopic:  Mean Free Path |
 74%
From NCERT
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When the gas in an open container is heated, the mean free path:

1. Increases
2. Decreases
3. Remains the same
4. Any of the above depending on the molar mass

Subtopic:  Mean Free Path |
 58%
From NCERT
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