The equation of state for 5g of oxygen at a pressure P and temperature T, when occupying a volume V, will be: (where R is the gas constant)
1. PV = 5 RT
2. PV = (5/2) RT
3. PV = (5/16) RT
4. PV = (5/32) RT

Uranium has two isotopes of masses 235 and 238 units. If both are present in Uranium hexafluoride gas, which would have the larger average speed?

A cylinder of fixed capacity \(44.8\) litres contains helium gas at standard temperature and pressure. What is the amount of heat needed to raise the temperature of the gas in the cylinder by \(15.0^\circ~\mathrm{C}?\) (\(R=8.31\) J mol^–1 K^–1)

To find out the degree of freedom, the correct expression is:

1. $f=\frac{2}{\gamma -1}$

2. $f=\frac{\gamma +1}{2}$

3. $f=\frac{2}{\gamma +1}$

4. $f=\frac{1}{\gamma +1}$

An increase in the temperature of a gas-filled in a container would lead to:

If \(C_p\) and \(C_v\) denote the specific heats (per unit mass) of an ideal gas of molecular weight \(M\) (where \(R\) is the molar gas constant), the correct relation is:
1. \(C_p-C_v=R\)
2. \(C_p-C_v=\frac{R}{M}\)
3. \(C_p-C_v=MR\)
4. \(C_p-C_v=\frac{R}{M^2}\)

The mean free path \(l\) for a gas molecule depends upon the diameter, \(d\) of the molecule as:
1. \(l\propto \frac{1}{d^2}\)
2. \(l\propto d\)
3. \(l\propto d^2 \)
4. \(l\propto \frac{1}{d}\)

Diatomic molecules like hydrogen have energies due to both translational as well as rotational motion. From the equation in kinetic theory, \(PV = \frac{2}{3}E\)$,$ \(E\) is:

1 mole of an ideal gas is contained in a cubical volume V, ABCDEFGH at 300 K (figure). One face of the cube (EFGH) is made up of a material which totally absorbs any gas molecule incident on it. At any given time:
                               

When an ideal gas is compressed adiabatically, its temperature rises: the molecules on an average have more kinetic energy than before. The kinetic energy increases: