At what temperature will the $$\text{rms}$$ speed of oxygen molecules become just sufficient for escaping from the earth's atmosphere?
(Given: Mass of oxygen molecule $$(m)= 2.76\times 10^{-26}~\text{kg}$$, Boltzmann's constant $$k_B= 1.38\times10^{-23}~\text{J K}^{-1}$$)
1. $$2.508\times 10^{4}~\text{K}$$
2. $$8.360\times 10^{4}~\text{K}$$
3. $$5.016\times 10^{4}~\text{K}$$
4. $$1.254\times 10^{4}~\text{K}$$

Subtopic:  Types of Velocities |
64%
From NCERT
NEET - 2018
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The molecules of a given mass of gas have rms velocity of 200 ms-1 at $$27^{\circ}\mathrm{C}$$ and 1.0 x 105 Nm-2 pressure. When the temperature and pressure of the gas are increased to, respectively, $$127^{\circ}\mathrm{C}$$ and 0.05 X 10Nm-2, rms velocity of its molecules in ms-1 will become:
1. 400/√3
2. 100√2/3
3. 100/3
4.100√2

Subtopic:  Types of Velocities |
79%
From NCERT
NEET - 2016
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The molecules of a given mass of gas have rms velocity of $$200~\mathrm{ms^{-1}}$$ at $$27^\circ \text{C}$$ and $$1.0\times 10^{5}~\mathrm{Nm^{-2}}$$ pressure. When the temperature and the pressure of the gas are respectively, $$127^\circ \text{C}$$ and $$0.05\times10^{5}~\mathrm{Nm^{-2}}$$, the RMS velocity of its molecules in $$\mathrm{ms^{-1}}$$ is:
1. $$\frac{400}{\sqrt{3}}$$
2. $$\frac{100\sqrt{2}}{3}$$
3. $$\frac{100}{3}$$
4. $$100\sqrt{2}$$
Subtopic:  Types of Velocities |
82%
From NCERT
NEET - 2016
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