A thermodynamic system undergoes a cyclic process \(ABCDA\) as shown in Fig. The work done by the system in the cycle is: 
             
1. \( P_0 V_0 \)
2. \( 2 P_0 V_0 \)
3. \( \frac{P_0 V_0}{2} \)
4. zero

In the cyclic process shown in the pressure-volume \((P-V)\) diagram, the change in internal energy is equal to:

1. $\pi {\left(\frac{{\mathrm{P}}_2-{\mathrm{P}}_1}{2}\right)}^2$

2. $\mathrm{\pi }{\left(\frac{{\mathrm{V}}_2-{\mathrm{V}}_1}{2}\right)}^2$

3. $\frac{\mathrm{\pi }}{4}({\mathrm{P}}_2-{\mathrm{P}}_1)({\mathrm{V}}_2-{\mathrm{V}}_1)$

4. zero

ABCA is a cyclic process. Its P-V graph would be:

1.		2.
3.		4.

For the indicator diagram given below, which of the following is not correct?

In the P-V diagram shown, the gas does 5 J of work in the isothermal process ab and 4 J in the adiabatic process bc. What will be the change in internal energy of the gas in the straight path from c to a? 

1. 9J 

2. 1 J

3. 4 J 

4. 5 J

In a cyclic process, the internal energy of the gas: