The cylindrical tube of a spray pump has a radius \(R,\) one end of which has \(n\) fine holes, each of radius \(r.\) If the speed of the liquid in the tube is \(v,\) the speed of the ejection of the liquid through the holes is:

1. \(\dfrac{vR^{2}}{n^{2}r^{2}}\) 2. \(\dfrac{vR^{2}}{nr^{2}}\)
3. \(\dfrac{vR^{2}}{n^{3}r^{2}}\) 4. \(\dfrac{v^{2}R}{nr}\)
Subtopic:  Equation of Continuity |
 79%
From NCERT
NEET - 2015
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