- 1(current)
Q. No.(Given density of water = \(10^3 ~\text{kgm}^{-3},~ g=10 ~\text{ms}^{-2} \) and \(1~\text{atm} = 10^5~\text{Pa}\))
| 1. | \(1~\text{atm}\) | 2. | \(2~\text{atm}\) |
| 3. | \(3~\text{atm}\) | 4. | \(4~\text{atm}\) |
| 1. | The coefficient of viscosity is a scalar quantity. |
| 2. | Surface tension is a scalar quantity. |
| 3. | Pressure is a vector quantity. |
| 4. | Relative density is a scalar quantity. |
| 1. | pressure on the base area of vessels \(A\) and \(B\) is the same. |
| 2. | pressure on the base area of vessels \(A\) and \(B\) is not the same. |
| 3. | both vessels \(A\) and \(B\) weigh the same. |
| 4. | vessel \(B\) weighs twice that of \(A\). |
A barometer is constructed using a liquid (density = \(760~\text{kg/m}^3\)). What would be the height of the liquid column, when a mercury barometer reads \(76~\text{cm}?\)
(the density of mercury = \(13600~\text{kg/m}^3\))
| 1. | \(1.36~\text m\) | 2. | \(13.6~\text m\) |
| 3. | \(136~\text m\) | 4. | \(0.76~\text m\) |
In a U-tube, as shown in the figure, the water and oil are in the left side and right side of the tube respectively. The height of the water and oil columns are \(15~\text{cm}\) and \(20~\text{cm}\) respectively. The density of the oil is:
\(\left[\text{take}~\rho_{\text{water}}= 1000~\text{kg/m}^{3}\right]\)
| 1. | \(1200~\text{kg/m}^{3}\) | 2. | \(750~\text{kg/m}^{3}\) |
| 3. | \(1000~\text{kg/m}^{3}\) | 4. | \(1333~\text{kg/m}^{3}\) |
A \(U\text-\)tube with both ends open to the atmosphere is partially filled with water. Oil, which is immiscible with water, is poured into one side until it stands at a level of \(10~\text{mm}\) above the water level on the other side. Meanwhile, the water rises by \(65~\text{mm}\) from its original level (see diagram). The density of the oil is:
| 1. | \(425~\text{kg m}^{-3}\) | 2. | \(800~\text{kg m}^{-3}\) |
| 3. | \(928~\text{kg m}^{-3}\) | 4. | \(650~\text{kg m}^{-3}\) |
The heart of a man pumps \(5~\text{L}\) of blood through the arteries per minute at a pressure of \(150~\text{mm}\) of mercury. If the density of mercury is \(13.6\times10^{3}~\text{kg/m}^{3}\) \(g = 10~\text{m/s}^2,\) then the power of the heart in watts is:
| 1. | \(1.70\) | 2. | \(2.35\) |
| 3. | \(3.0\) | 4. | \(1.50\) |
The approximate depth of an ocean is \(2700~\text{m}\). The compressibility of water is \(45.4\times10^{-11}~\text{Pa}^{-1}\) and the density of water is \(10^{3}~\text{kg/m}^3\). What fractional compression of water will be obtained at the bottom of the ocean?
| 1. | \(0.8\times 10^{-2}\) | 2. | \(1.0\times 10^{-2}\) |
| 3. | \(1.2\times 10^{-2}\) | 4. | \(1.4\times 10^{-2}\) |
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Q. No.
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